我需要从一个包含4个名称空间的xml文件中创建一个查询,但是它们都没有唯一的ID。例如。 xmlns:fb
我在下面列出了它们:
xmlns="http://xxx/pie/svc/frs/FindRegistration/2.0.0"
xmlns="http://xxx/pie/xsd/frs/FindRegistrationMessages/2.0.0"
xmlns="http://xxx/pie/xsd/common/CommonCoreElements/2.0.0"
xmlns="http://xxx/pie/xsd/frs/PractitionerRegistrationElements/2.0.0"
如果我从文档中剥离了所有名称空间(通过Visual Studio),则可以很好地检索数据,但是我需要保持名称空间完整。
<FindRegistrationsResponse xmlns="http://xxx/pie/svc/frs/FindRegistration/2.0.0">
<AuditDetails xmlns="http://xxx/pie/xsd/frs/FindRegistrationMessages/2.0.0">
<QueryIdentifier xmlns="http://xxx/pie/xsd/common/CommonCoreElements/2.0.0">8901823</QueryIdentifier>
<PractitionerCount xmlns="http://xxx/pie/xsd/common/CommonCoreElements/2.0.0">134140</PractitionerCount>
<ServiceMessagesCount xmlns="http://xxx/pie/xsd/common/CommonCoreElements/2.0.0">2</ServiceMessagesCount>
<TotalRecordsSearched xmlns="http://xxx/pie/xsd/common/CommonCoreElements/2.0.0">134142</TotalRecordsSearched>
<TotalNumberOfRegistration xmlns="http://xxx/pie/xsd/common/CommonCoreElements/2.0.0">257034</TotalNumberOfRegistration>
<SnapshotDate xmlns="http://xxx/pie/xsd/common/CommonCoreElements/2.0.0">2018-06-29</SnapshotDate>
</AuditDetails>
<ProfessionNumberReplay ProfessionNumber="MED0000xxxxx" xmlns="http://xxx/pie/xsd/frs/FindRegistrationMessages/2.0.0">
<Practitioner>
<PractitionerIdentifier xmlns="http://xxx/pie/xsd/frs/PractitionerRegistrationElements/2.0.0">xxxxxxxx</PractitionerIdentifier>
<PractitionerName NameEditDate="2010-07-03T14:14:35.377" xmlns="http://xxx/pie/xsd/frs/PractitionerRegistrationElements/2.0.0">
<NameTitle>Dr</NameTitle>
<FamilyName>Smith</FamilyName>
<GivenName>John</GivenName>
<MiddleName />
</PractitionerName>
<Demographics xmlns="http://xxx/pie/xsd/frs/PractitionerRegistrationElements/2.0.0">
<Gender>GenderName</Gender>
</Demographics>
<Qualification QualificationEditDate="2016-08-10T19:35:54.067" xmlns="http://xxx/pie/xsd/frs/PractitionerRegistrationElements/2.0.0">
<QualificationTitle>Bachelor of Medicine / Bachelor of Surgery </QualificationTitle>
<AwardingInstitution>University of xxx</AwardingInstitution>
<CountryQualificationObtained>Country Name</CountryQualificationObtained>
<YearOfQualification>1999</YearOfQualification>
</Qualification>
<Address AddressEditDate="2010-07-03T14:15:48.607" xmlns="http://xxx/pie/xsd/frs/PractitionerRegistrationElements/2.0.0">
<AustralianAddress>
<AustralianLocality>SUBURB NAME</AustralianLocality>
<AustralianPostcode>2000</AustralianPostcode>
<AustralianState>NSW</AustralianState>
<Country>Australia</Country>
</AustralianAddress>
</Address>
<Profession xmlns="http://xxx/pie/xsd/frs/PractitionerRegistrationElements/2.0.0">
<ProfessionNumber>MED0000xxxxx</ProfessionNumber>
<Profession>Medical Practitioner</Profession>
<ProfessionStartDate>1999-05-10T00:00:00</ProfessionStartDate>
<Registration>
<RecordNumber>001</RecordNumber>
<RegistrationType>Limited (Public Interest - Occasional Practice)</RegistrationType>
<RegistrationStatus>Unregistered</RegistrationStatus>
<RegistrationSubStatus>Withdrawn</RegistrationSubStatus>
<RegistrationToDate>2013-09-30T00:00:00</RegistrationToDate>
<InitialRegistrationDate>1965-05-10T00:00:00</InitialRegistrationDate>
</Registration>
<Condition ConditionEditDate="2012-10-22T14:00:10.5">
<ConditionType>Registration</ConditionType>
<ConditionDetail>text here</ConditionDetail>
</Condition>
</Profession>
</Practitioner>
</ProfessionNumberReplay>
</FindRegistrationsResponse>
这是我尝试过的T-SQL代码:
DECLARE @XML AS XML, @hDoc AS INT, @SQL NVARCHAR (MAX)
SELECT @XML = XMLData FROM AHPRA_XML
EXEC sp_xml_preparedocument @hDoc OUTPUT, @XML
;WITH XMLNAMESPACES('http://xxx/pie/svc/frs/FindRegistration/2.0.0',
'http://xxx/pie/xsd/frs/FindRegistrationMessages/2.0.0',
'http://xxx/pie/xsd/common/CommonCoreElements/2.0.0',
'http://xxx/pie/xsd/frs/PractitionerRegistrationElements/2.0.0')
SELECT DISTINCT ProfessionNumber, NameTitle, GivenName, MiddleName, FamilyName, Gender
FROM OPENXML(@hDoc, 'FindRegistrationsResponse/ProfessionNumberReplay/Practitioner')
WITH
(
ProfessionNumber [varchar](50) '../@ProfessionNumber',
NameTitle [varchar](20) 'PractitionerName/NameTitle',
GivenName [varchar](100) 'PractitionerName/GivenName',
MiddleName [varchar](100) 'PractitionerName/MiddleName',
FamilyName [varchar](100) 'PractitionerName/FamilyName',
Gender [varchar](10) 'Demographics/Gender'
)
EXEC sp_xml_removedocument @hDoc
GO
答案 0 :(得分:2)
您已经定义了名称空间-但您从未在XPath中使用!另外,我强烈建议在内置的OPENXML
方法之上使用内置的XQuery功能。
尝试以下选择语句:
;WITH XMLNAMESPACES('http://xxx/pie/svc/frs/FindRegistration/2.0.0' AS root,
'http://xxx/pie/xsd/frs/FindRegistrationMessages/2.0.0' AS msg,
'http://xxx/pie/xsd/frs/PractitionerRegistrationElements/2.0.0' AS el)
SELECT
ProfessionNumber = XC.value('(../@ProfessionNumber)', 'varchar(50)'),
NameTitle = XC.value('(el:PractitionerName/el:NameTitle)[1]', 'varchar(50)'),
GivenName = XC.value('(el:PractitionerName/el:GivenName)[1]', 'varchar(50)'),
MiddleName = XC.value('(el:PractitionerName/el:MiddleName)[1]', 'varchar(50)'),
FamilyName = XC.value('(el:PractitionerName/el:FamilyName)[1]', 'varchar(50)'),
Gender = XC.value('(el:Demographics/el:Gender)[1]', 'varchar(50)')
FROM
@XML.nodes('/root:FindRegistrationsResponse/msg:ProfessionNumberReplay/msg:Practitioner') AS XT(XC)
这应该从XML字符串中获取所需的数据。
更新:
当您在问题中提供的XML以及此处的代码时,您确实会得到以下输出:
因此,您可能不是真的在使用提供的示例XML,或者您正在使用其他代码……