Question

在一开始时，值得注意的是我是Python的初学者。我的if陈述有问题。我正在尝试写一条线，该线将检查玩家是否选择X或O而不是其他角色。所以我用那条线来做到这一点：

if player_x_or_o == 'X' or 'O':
    setplayermove(row_choice, col_choice)
else:
    print('Invalid value, try again.')

但是，如果有人使用，例如“ S”，则程序将首先执行if而不是else。我不明白为什么，有什么想法吗？

# functions


def game_board(X_or_O=0, row=0, column=0, show_gb=False):
    print('     1  2  3')
    if not show_gb:
        game[row][column] = X_or_O
    for index, listof0 in enumerate(game):
        index += 1
        print(index,'.',listof0)

def setplayermove(row, col):
    game[row_choice][col_choice] = player_x_or_o


# Game board

game = [[0,0,0],
        [0,0,0],
        [0,0,0]]

game_board(show_gb=False)

# User input

while True:
    player_x_or_o = str(input('Do you want put "X" or "O"? \n'))
    row_choice = int(input('In which row do you want set your {}? \n'.format(player_x_or_o)))
    col_choice = int(input('In which column do you want set your {}? \n'.format(player_x_or_o)))
    row_choice -= 1
    col_choice -= 1

    if player_x_or_o == 'X' or 'O':
        setplayermove(row_choice, col_choice)
    else:
        print('Invalid value, try again.')



    game_board(show_gb=True)

Answer 1

我认为这行是错误的：

if player_x_or_o == 'X' or 'O':

您可能要写的是：

if player_x_or_o == 'X' or player_x_or_o == 'O':

Answer 2

第二个条件始终为真，请尝试如下更改条件：

if player_x_or_o == 'X' or player_x_or_o == 'O'

程序忽略“ else”语句

2 个答案: