Question

我正在Nodejs上制作一个小应用程序，并且正在努力循环一个不规则的JSON以打印其数据。

我的JSON具有下一个结构：

{
"courses": [
    {
        "java": [
            { "attendees": 43 },
            { "subject": "Crash course" }
        ]
    },
    {
        "python":
        {
            "occurrences": [
                { "attendees": 24 },
                { "subject": "another crash course" },
                { "notes": "completed with issues" }
            ,
                { "attendees": 30 },
                { "subject": "another crash course" },
                { "notes": "completed with issues" }
            ]
        }
    }
],
"instructors":[
    {
        "John Doe":[
            { "hours": 20 },
            { "experience": 50 },
            { "completed": true }
        ]
    },
    {
        "Anne Baes": [
            { "hours": 45 },
            { "experience": 40 },
            { "completed": false},
            { "prevExperience": true}
        ]
    }
]
}

我想做的是打印JSON中包含的所有数据（我想要类似的东西）：

courses
Java
attendees = 43
...
Anne Baes
hours = 45
experience = 40
completed = false
prevExperience = true

我尝试过：

for(element in data){
    console.log(`element = ${{element}}`);
}

并且仅打印：

element = [object Object]
element = [object Object]

（这很有意义，因为json由两个元素组成）

我尝试过嵌套行：

for(element in data){

这里的问题是有一个不规则的结构，我的意思是，“ java”和“ python”是同一级别的数据，但同时它们具有不同的（数组和对象）值类型，并且在“讲师”的价值观类型相同，但价值观的数量不同。

有人可以帮我吗？：（

Answer 1

您可以使用递归和for..in循环

const obj = {
"courses": [
    {
        "java": [
            { "attendees": 43 },
            { "subject": "Crash course" }
        ]
    },
    {
        "python":
        {
            "occurrences": [
                { "attendees": 24 },
                { "subject": "another crash course" },
                { "notes": "completed with issues" }
            ,
                { "attendees": 30 },
                { "subject": "another crash course" },
                { "notes": "completed with issues" }
            ]
        }
    }
],
"instructors":[
    {
        "John Doe":[
            { "hours": 20 },
            { "experience": 50 },
            { "completed": true }
        ]
    },
    {
        "Anne Baes": [
            { "hours": 45 },
            { "experience": 40 },
            { "completed": false},
            { "prevExperience": true}
        ]
    }
]
};
function print(obj,isArr = false){
  for(let key in obj){
    if(typeof obj[key] === 'object'){
      if(isArr === false) console.log(key)
      print(obj[key],Array.isArray(obj[key]));
    }
    else console.log(`${key} = ${obj[key]}`)
  }
}
print(obj)

Answer 2

您可以尝试使用像这样的递归函数迭代这些值

var Obj {

//Contents

}

function printRec(obj){
if(Object.keys(obj).length>0||Array.isArray(obj)){
  for(elem in obj){
  printRec(obj);
  }
}else{
  //Process Value
  console.log(obj)
}
}

如何使用节点js遍历不规则的嵌套json

2 个答案: