sf:将纬度/经度从几何体写入单独的列并保留ID列

时间:2019-02-17 15:35:43

标签: r sf

我有一个来自shapefile的带有多边形ID的df及其在几何列中的中心点:

# A tibble: 3 x 2
     ID     geometry
  <dbl> <POINT [°]>
1     1 (117.2 31.8)
2     2 (116.4 40.1)
3     4   (117.9 26)

我想将纬度/经度值放在单独的列中,所以我这样做:

library(sf)
centres<- as.data.frame(st_coordinates(df))

此新的“中心”数据框具有经度和纬度值,但未找到ID列。 如何保存它,还是有另一种方法将纬度和经度值从几何列分离到不同的列中,同时将ID保持在同一df中?

数据框的

dput是:

df <- structure(list(ID = c(1, 2, 4), 
      geometry = structure(list(structure(c(117.2, 31.8), 
      class = c("XY", "POINT", "sfg")), structure(c(116.4, 40.1), 
      class = c("XY", "POINT", "sfg")), structure(c(117.9, 26.0), 
      class = c("XY", "POINT", "sfg"))), class = c("sfc_POINT", "sfc"), 
      precision = 0, bbox = structure(c(xmin = 116.4, ymin = 26.0, xmax = 117.9, ymax = 40.1), 
      class = "bbox"), crs = structure(list(epsg = 4326L, 
      proj4string = "+proj=longlat +datum=WGS84 +no_defs"), class = "crs"), n_empty = 0L)), 
      row.names = c(NA, -3L), class = c("sf", "tbl_df", "tbl", "data.frame"), 
      sf_column = "geometry", agr = structure(c(ID = NA_integer_), 
      class = "factor", .Label = c("constant", "aggregate", "identity")))

3 个答案:

答案 0 :(得分:5)

st_geometry可以与dplyr::mutate一起使用:

library(magrittr) #for the pipe
df <- df %>%
  dplyr::mutate(lat = sf::st_coordinates(.)[,1],
                lon = sf::st_coordinates(.)[,2])

df
Simple feature collection with 3 features and 3 fields
geometry type:  POINT
dimension:      XY
bbox:           xmin: 116.4 ymin: 26 xmax: 117.9 ymax: 40.1
CRS:            EPSG:4326
# A tibble: 3 x 4
     ID     geometry   lon   lat
* <dbl>  <POINT [°]> <dbl> <dbl>
1     1 (117.2 31.8)  117.  31.8
2     2 (116.4 40.1)  116.  40.1
3     4   (117.9 26)  118.  26 

如果您不再关心geometry,请使用df %>% sf::st_set_geometry(NULL)

转换为标准数据框

答案 1 :(得分:0)

使用unlist + map()的解决方案

library(tidyverse)

separated_coord <- df %>%
    mutate(lat = unlist(map(df$geometry,1)),
           long = unlist(map(df$geometry,2)))

separated_coord

答案 2 :(得分:0)

一种可能的方法是将其取消列出。

setNames(data.frame(df[[1]], 
                    matrix(unlist(df[2]), ncol=2, byrow=TRUE)), 
         c("ID", "lon", "lat"))

#   ID   lon  lat
# 1  1 117.2 31.8
# 2  2 116.4 40.1
# 3  4 117.9 26.0

说明

使用str(df)进行的数据结构检查显示,变量geometry-的格式为list,可能不方便。解决此问题的一种方法是unlist(),将其转换为2列矩阵,然后将其与第一列重新组合。使用setNames(),我们可以一步分配新的列名。