每当通过按Enter提交搜索表单时,我都会使用AJAX调用来获取我的同乐物品。我想删除以前的项目,并在按Enter键时将新项目添加到回旋中。
除重复按Enter键外,它一直都有效,它不会删除旧项,而只是不断添加新项。
function removeResult() {
var i = 0;
$("#result_section").slideUp(750, function () {
$('.result_item').each(function(){
$(".prof-carousel").trigger('remove.owl.carousel', [i++])
.trigger('refresh.owl.carousel');
});
});
}
$("#index_search_btn").click(function (e) {
e.preventDefault();
removeResult();
var formData = new FormData();
formData.append('type', search_type);
formData.append('q', search_q);
$.ajax({
type: "POST",
contentType: false,
processData: false,
url: "/search",
data: formData,
success: function (response) {
$("#result_section").slideDown(750, function () {
$.each(response, function (index, prof) {
var item = '';
item += '<div class="item carousel_ostad_item result_item">'+ 'whatever...'+'</div>';
$('.my-carousel').owlCarousel().trigger('add.owl.carousel',[jQuery(item)]).trigger('refresh.owl.carousel');
});
});
},
error: function (xhr, ajaxOptions, thrownError) {
alert(xhr.status + " " + thrownError);
}
});
});
答案 0 :(得分:0)
可能是因为Ajax异步且速度较慢,并且发生了类似以下事情:
Enter -> Remove (old el) -> Ajax call 1 -> Enter -> Remove (nothing) -> Ajax call 2 -> Ajax callback 1 ADD -> Ajax callback 2 ADD
我希望这很清楚,我不知道该如何表达。
您可以做的是删除success
Ajax回调中的旧元素。
$("#index_search_btn").click(function (e) {
e.preventDefault();
// #### Remove this...
//removeResult();
var formData = new FormData();
formData.append('type', search_type);
formData.append('q', search_q);
$.ajax({
type: "POST",
contentType: false,
processData: false,
url: "/search",
data: formData,
success: function (response) {
// ... and move here. ####
removeResult();
$("#result_section").slideDown(750, function () {
$.each(response, function (index, prof) {
var item = '';
item += '<div class="item carousel_ostad_item result_item">'+ 'whatever...'+'</div>';
$('.my-carousel').owlCarousel().trigger('add.owl.carousel',[jQuery(item)]).trigger('refresh.owl.carousel');
});
});
}, error: function (xhr, ajaxOptions, thrownError) {
alert(xhr.status + " " + thrownError);
}
});
});
答案 1 :(得分:0)
我确实提出了一个简单的解决方案。 按下搜索按钮后,我禁用了搜索按钮(因此该表单无法重复提交),并在成功的Ajax回调中添加了回旋项之后再次启用了它。
$("#index_search_btn").click(function (e) {
e.preventDefault();
///// disable search button /////
$("#index_search_btn").attr("disabled", true);
removeResult();
var formData = new FormData();
formData.append('type', search_type);
formData.append('q', search_q);
$.ajax({
type: "POST",
contentType: false,
processData: false,
url: "/search",
data: formData,
success: function (response) {
$("#result_section").slideDown(750, function () {
$.each(response, function (index, prof) {
var item = '';
item += '<div class="item carousel_ostad_item result_item">'+ 'whatever...'+'</div>';
$('.my-carousel').owlCarousel().trigger('add.owl.carousel',[jQuery(item)]).trigger('refresh.owl.carousel');
///// enable search button /////
$("#index_search_btn").removeAttr("disabled");
});
});
}, error: function (xhr, ajaxOptions, thrownError) {
alert(xhr.status + " " + thrownError);
}
});
});