Question

我收到此警告：

mysqli_query（）期望参数2为字符串，对象在第25行的C：\ xampp \ htdocs \ c1 \ details_save.php未知列 “字段列表”中的“ combo_id”

    <?php 
     session_start();
     include('includes/dbcon.php');

      $id = $_SESSION['id'];
      $venue = $_POST['venue'];
      $date = $_POST['date'];
      $time = $_POST['time'];
      $motif = $_POST['motif'];
      $pax = $_POST['pax'];
      $type = $_POST['type'];
      $ocassion = $_POST['ocassion'];
      $cid = $_POST['combo_id'];
      $date=date("Y-m-d",strtotime($date));

      $query = mysqli_query($con, "SELECT * FROM `reservation` WHERE r_date='".$date."' AND r_status = 'Approved'");
        if(mysqli_num_rows($query) > 0)
        {

                echo "<script>alert ('Date is already reserved');
                window.history.back(); </script>";
        }
        else{
            if (!mysqli_query($con,$query))
            {
               $query = mysqli_query($con, "SELECT * FROM combo WHERE combo_id='$cid'");
               $row=mysqli_fetch_array($query);
               $price=$row['combo_price'];
               $payable=$pax*$price;

               mysqli_query($con,"UPDATE reservation SET payable='$payable',balance='$payable',r_venue='$venue',r_date='$date',r_time='$time',r_motif='$motif',r_ocassion='$ocassion',r_type='$type',pax='$pax',combo_id='$cid',price='$price' where rid='$id'")or die(mysqli_error($con)); 

             $_SESSION['id']=$id;


             echo "<script>document.location='payment.php'</script>";   
            }}

           ?>

Answer 1

您需要按以下方式更改代码：

session_start();
include('includes/dbcon.php');

$id = $_SESSION['id'];
$venue = $_POST['venue'];
$date = $_POST['date'];
$time = $_POST['time'];
$motif = $_POST['motif'];
$pax = $_POST['pax'];
$type = $_POST['type'];
$ocassion = $_POST['ocassion'];
$cid = $_POST['combo_id'];
$date = date("Y-m-d", strtotime($date));

$selectQuery = "SELECT * FROM `reservation` WHERE r_date='" . $date . "' AND r_status = 'Approved'";
$query = mysqli_query($con, $selectQuery);
if (mysqli_num_rows($query) > 0) {

    echo "<script>alert ('Date is already reserved');
                window.history.back(); </script>";
} else {
//    if (!mysqli_query($con, $selectQuery)) { // no need to apply this condition
        $query = mysqli_query($con, "SELECT * FROM combo WHERE combo_id='$cid'");
        $row = mysqli_fetch_array($query);
        $price = $row['combo_price'];
        $payable = $pax * $price;

        mysqli_query($con, "UPDATE reservation SET payable='$payable',balance='$payable',r_venue='$venue',r_date='$date',r_time='$time',r_motif='$motif',r_ocassion='$ocassion',r_type='$type',pax='$pax',combo_id='$cid',price='$price' where rid='$id'")or die(mysqli_error($con));

        $_SESSION['id'] = $id;


        echo "<script>document.location='payment.php'</script>";
//    }
}
?>

您不需要检查if(!mysql_query($con, $query))。您可以简单地在其他条件下编写代码。希望对您有帮助。

如何清除此警告：mysqli_query（）期望参数2为字符串？

1 个答案: