Question

我编写了一条代码，使用try和except捕获错误消息（我想不使用isinstance编写它），并且输入不是整数时，我会收到错误消息。问题是，即使输入是有效整数，程序也会给我错误消息。请给我一些建议以使其运行。我的代码如下：

我尝试使用异常子句，但这没用。

class Hotel:
    def __init__(self,room,catagory):
        if room != int:
            raise TypeError ()
        self.room = room
        self.catagory = catagory
        self.catagories = {"A":"Elite","B":"Economy","C":"Regular"}
        self.rooms = ["0","1","2","3","4","5"]

    def getRoom(self):
        return self.room

    def getCatagory(self):
        return self.catagory
        return self.catagories.get(self.catagory)
    def __str__(self):
        return "%s and %s"%(self.rooms[self.room],self.catagories.get(self.catagory))
try:
    room1 = Hotel(a,"A")
    room2 = Hotel(1,"A")
    print(room1.getRoom())
except:
    print("there's an error")

我期望：

有错误

1和精英

A

Answer 1

您正在检查room != int是否。它总是会给你错误。

您必须检查type(room)!= int。我已更正下面的代码

class Hotel:
    def __init__(self,room,catagory):
        if type(room) != int:
            raise TypeError ()
        self.room = room
        self.catagory = catagory
        self.catagories = {"A":"Elite","B":"Economy","C":"Regular"}
        self.rooms = ["0","1","2","3","4","5"]

代替isinstance，在Python 3.7中使用try和except

1 个答案: