Question

我正在尝试过滤教授表以显示与特定学校和特定专业相对应的教授，错误消息中显示了参数，我只是根本不理解为什么有错误消息

Views.py

from django.http import HttpResponse
from django.shortcuts import render
from .models import professor, School, Major, School_Major

def index(request):
    schools = School.objects.all()
    return render(request, 'locate/index.html', {'schools': schools})


# def Major(request, Major):
#   major_choice = professor.objects.filter(Major =Major)
#   return render(request, 'locate/major.html', {'major_choice': major_choice})

def Majors(request, school_pk):
    schools_majors_ids = []
    major_after_filter = []

    #Filter to a show the association of 1 schools majors
    school_choice = School_Major.objects.filter(school_id = school_pk)

    #Append each of the major id's to school_majors_ids list
    for store in school_choice:
        schools_majors_ids.append(store.major_id)

    #Filter majors names required
    for store in schools_majors_ids:
        name = Major.objects.get(id = store)
        major_after_filter.append(name)
    return render(request, 'locate/major.html', {'major_after_filter' : major_after_filter,
                                                 'school_pk' : school_pk})

def Professors(request, school_pk, major_pk):
    professors = professors.objects.filter(school_id = school_pk).filter(major_id = major_pk)
    return render(request, 'locate/professors', {'professors' : professors})

url.py

from django.urls import path

from . import views


urlpatterns = [
    path('', views.index, name='index'),
    path(' <int:school_pk>/', views.Majors, name='Major'),
    path(' <int:school_pk/<int:major_pk>/', views.Professors, name="Professors")
]

majors.html

<h3 id="test">{{school_pk}}</h3>
            <ul>
                {% for major in major_after_filter %}

                <li><a href="{% url 'Professors' school_pk major.id %}">{{major.name}}</a></li>

                {%endfor%}
            </ul>

我需要一种方法来设置学校主键的值以及专业主键的值作为Profess视图功能的参数，以便能够筛选出Professor表以显示正确的专业。

当我离开school_pk时，如下所示

我收到以下错误

django.urls.exceptions.NoReverseMatch: Reverse for 'Professors' with arguments '(1, 5)' not found. 1 pattern(s) tried: ['locate/\\ <int:school_pk/(?P<major_pk>[0-9]+)/$']

当我删除如下所示的school_pk时

<li><a href="{% url 'Professors' major.id %}">{{major.name}}</a></li>

我收到此错误

TypeError: Professors() missing 1 required positional argument: 'school_pk'

这是有道理的，因为Professor函数需要一个school_pk参数（请注意，如果html和parameter中使用的变量令人困惑，则将其命名为相同的遗憾。

Answer 1

您在网址格式中缺少右括号。

path('<int:school_pk>/<int:major_pk>/', 
                    ^

django.urls.exceptions.NoReverseMatch：找不到具有参数'（1，5）'的'教授'的反向

1 个答案: