Question

SELECT 
  cms_module_ladu_batch.id AS batch_id, 
  name, t1, cms_module_ladu_batch.date_changed AS date_ch, 
  t13, t2, t3, t4, bkuup, date_modified, date_created, 
  kogused.aadress AS aadress, 
  kogused.kogus AS kogus, 
  SUM(kogused.kogus) AS total 
FROM 
  cms_module_ladu_batch 
  LEFT JOIN kogused 
    ON cms_module_ladu_batch.id = kogused.bid 
WHERE 
  t2!='Sildid' 
GROUP BY 
  batch_id

这就是MySQL代码 - 问题如下。我需要排除total为0且date_ch早于一个月的行（date_cd格式为“2011-01-01 00:00:00”）。可能吗？ http://jsfiddle.net/tiitremmel/2mvrr/1/ - jsfiddle示例 - 第一个表就像mysql结果是默认的，第二个表是结果的样子。

Answer 1

将日期条件添加到WHERE - 语句中，并将SUM排除在外 HAVING - 声明。它应该是这样的：

SELECT    cms_module_ladu_batch.id AS batch_id,
          cms_module_ladu_batch.date_changed AS date_ch,
          kogused.kogus AS kogus,
          SUM(kogused.kogus) AS total 
FROM      cms_module_ladu_batch 
LEFT JOIN kogused ON cms_module_ladu_batch.id = kogused.bid 
WHERE     t2 != 'Sildid' 
          AND (
                  (
                   cms_module_ladu_batch.date_changed < DATE_SUB(NOW(), INTERVAL 1 MONTH)
                   AND SUM(kogused.kogus) > 0
                  )
              OR
                  cms_module_ladu_batch.date_changed > DATE_SUB(NOW(), INTERVAL 1 MONTH)
              )
GROUP BY  batch_id;

或者......使用UNION-Statement将两个SELECTS粘合在一起。

SELECT   cms_module_ladu_batch.id AS batch_id,
         cms_module_ladu_batch.date_changed AS date_ch,
         kogused.kogus AS kogus,
         SUM(kogused.kogus) AS total 
FROM     cms_module_ladu_batch 
LEFT JOIN kogused ON cms_module_ladu_batch.id = kogused.bid 
WHERE t2 != 'Sildid' 
         AND cms_module_ladu_batch.date_changed < DATE_SUB(NOW(), INTERVAL 1 MONTH)
GROUP BY batch_id 
HAVING total > 0
UNION
SELECT   cms_module_ladu_batch.id AS batch_id,
         cms_module_ladu_batch.date_changed AS date_ch,
         kogused.kogus AS kogus,
         SUM(kogused.kogus) AS total 
FROM     cms_module_ladu_batch 
LEFT JOIN kogused ON cms_module_ladu_batch.id = kogused.bid 
WHERE t2 != 'Sildid' 
         AND cms_module_ladu_batch.date_changed > DATE_SUB(NOW(), INTERVAL 1 MONTH)
GROUP BY batch_id;

尝试两者，看看最适合您的解决方案。

Answer 2

SELECT 
  cms_module_ladu_batch.id AS batch_id, 
  name, t1, cms_module_ladu_batch.date_changed AS date_ch, 
  t13, t2, t3, t4, bkuup, date_modified, date_created, 
  kogused.aadress AS aadress, 
  kogused.kogus AS kogus, 
  SUM(kogused.kogus) AS total 
FROM 
  cms_module_ladu_batch 
  LEFT JOIN kogused 
    ON cms_module_ladu_batch.id = kogused.bid 
WHERE 
  t2!='Sildid' AND
  date_ch < date_sub(now(), interval 1 month)
GROUP BY 
  batch_id
HAVING 
  SUM(kogused.kogus) <> 0

Answer 3

要在GROUP BY子句之外进行过滤，您可以使用HAVING关键字。

http://dev.mysql.com/doc/refman/5.5/en/select.html

Answer 4

只需在底部添加：

HAVING (total<>0) AND (date_cd>=ADDDATE(CURDATE(), INTERVAL -1 MONTH))

其他回复（见评论）：

HAVING (total<>0) OR (date_cd>=ADDDATE(CURDATE(), INTERVAL -1 MONTH))

Answer 5

    SELECT    cms_module_ladu_batch.id AS batch_id,
          cms_module_ladu_batch.date_changed AS date_ch,
          kogused.kogus AS kogus,
          SUM(kogused.kogus) AS total 
FROM      cms_module_ladu_batch 
LEFT JOIN kogused ON cms_module_ladu_batch.id = kogused.bid 
WHERE     t2 != 'Sildid' 
GROUP BY  batch_id
HAVING    (
       (
          cms_module_ladu_batch.date_changed < DATE_SUB(NOW(), INTERVAL 1 MONTH)
          AND SUM(kogused.kogus) > 0
       )
    OR
           cms_module_ladu_batch.date_changed > DATE_SUB(NOW(), INTERVAL 1 MONTH)
           );

这是最适合我的代码。非常感谢所有人，但对Bjoern最重要 - 你对代码的想法对我帮助很大！

MySQL如何在两个子句中包含哪些内容？

5 个答案: