我想操作表格1中的“ AS年龄”列

Question

下面是我写的查询

SELECT *, YEAR(CURDATE()) - YEAR(age) AS age FROM table1

并且我想操作以上查询中的“年龄”列

例如：

SELECT  * FROM table1 WHERE age BETWEEN 1 AND 9

如何从此查询中完成

SELECT *, YEAR(CURDATE()) - YEAR(age) AS age FROM table1

我的结果将返回包含年龄范围的行

Answer 1

您可以像使用

一样将query用作subquery

SELECT t2.* FROM
( SELECT t1.*, YEAR(CURDATE()) - YEAR(age) AS age FROM table1 t1 ) t2
WHERE t2.age BETWEEN 1 and 9

Answer 2

MySQL为 g++ -Ic:\ProgramData\Anaconda3\include -Lc:\ProgramData\Anaconda3\libs test.cpp 子句提供了扩展，允许您执行所需的操作：

HAVING

注意：我假设您想要某种年份的 date 列。花一年的时间称为SELECT *, YEAR(CURDATE()) - YEAR(date) AS age FROM table1 HAVING age BETWEEN 1 AND 9; 并没有任何意义。