我申请了有关系统安全性主题的报告。 Caesar的快速代码。并且在解密阶段遇到了一个问题。
当我输入密钥时,程序会随机剔除错误:
Thread 1: Fatal error: Unexpectedly found nil while unwrapping an Optional value
或者数组退出错误
我是新手。请向我解释如何解决此错误并使程序正常运行。
Google没有帮助我。
import UIKit
class CaesarCipher: UIViewController {
@IBOutlet weak var messageText: UITextField!
@IBOutlet weak var keyText: UITextField!
@IBOutlet weak var cipherTextLabel: UILabel!
////////////////////////////////////////////////////////////////////////////
@IBOutlet weak var cryptMessageText: UITextField!
@IBOutlet weak var cryptKeyText: UITextField!
@IBOutlet weak var decryptTextLabel: UILabel!
@IBAction func cipherButton(_ sender: Any) {
if (messageText.text == "") || (keyText.text == "")
{
let alert = UIAlertController(title: "Ошибка", message: "Одно, или несколько полей пустые", preferredStyle: .alert)
alert.addAction(UIAlertAction(title: "Ок", style: .default, handler: nil))
self.present(alert, animated: true)
}
else
{
let key = keyText.text
let e: Int32 = Int32.init(key!)!
//let upKey: Int32 = Int32.init(&e)
let messageCipher = messageText.text
// var i: Int8 = Int8.init(messageCipher!)!
//let up: UnsafeMutablePointer<Int8> = UnsafeMutablePointer<Int8>.init(&i)
//cipherTextLabel = encrypt(up, e)
let encryptText = cipher(messageCipher!, shift: Int(e))
cipherTextLabel.text = "\(encryptText)"
}
}
//////////////////////////////////////////////////////////////////////////////////////////////
@IBAction func decryptButton(_ sender: Any) {
if (cryptMessageText.text == "") || (cryptKeyText.text == "")
{
let alert = UIAlertController(title: "Ошибка", message: "Одно, или несколько полей пустые", preferredStyle: .alert)
alert.addAction(UIAlertAction(title: "Ок", style: .default, handler: nil))
self.present(alert, animated: true)
}
else
{
let cryptKey = cryptKeyText.text
let e: Int = Int.init(cryptKey!)!
//let upKey: Int32 = Int32.init(&e)
let decryptMessageText = cryptMessageText.text
// var i: Int8 = Int8.init(messageCipher!)!
//let up: UnsafeMutablePointer<Int8> = UnsafeMutablePointer<Int8>.init(&i)
//cipherTextLabel = encrypt(up, e)
let decryptText = decipher(decryptMessageText!, shift2: Int(e))
decryptTextLabel.text = "\(decryptText)"
}
}
override func viewDidLoad() {
super.viewDidLoad()
self.hideKeyboard()
}
}
func cipher( _ text:String, shift:Int ) -> String {
var textCharArray:[Character] = Array( text.characters )
let alphabet = Array("0123456789abcdefghijklmnopqrstuvxyzABCDEFGHIJKLMNOPQRSTUWVXYZ !".characters);
let offset = alphabet.count // alphabet.length in other languages
for i in 0 ..< text.characters.count {
let oldChar = textCharArray[ i ]
let oldCharIdx = alphabet.index( of:oldChar ) // get index of
let oldCharIdxUnwrapped = oldCharIdx // oldCharIdx can be null!
let newCharIdx = ( oldCharIdxUnwrapped! + shift + offset ) % offset
let newChar = alphabet[ newCharIdx ]
textCharArray[ i ] = newChar
}
return String( textCharArray )
}
func decipher( _ text:String, shift2:Int ) -> String {
// when calling a function you don't have to specify the first argument...
// For other arguments you have to specify it!
return cipher( text, shift:shift2 * -1 )
}
答案 0 :(得分:0)
当看到一个Optional(一个可能为nil的值)并且尝试将其解包(使用'!')时,通常会抛出该错误。
Swift还引入了可选类型,用于处理不存在的 值。可选说“有一个值,它等于x”或 “根本没有价值”。
话虽这么说,这里的问题是UITextfields为“空”时其text属性可能为nil。所以当你做
let key = keyText.text
let e: Int32 = Int32.init(key!)!
key
可以为nil值。而(nil)!
将产生Unexpectedly found nil while unwrapping an Optional value
。
要解决此问题,建议您为UITextfield的text属性添加一个nil检查,或者
将您的if else
块更改为以下
if let key = keyText.text, let messageCipher = messageText.text, !key.isEmpty, !messageCipher.isEmpty {
// key and messageCipher are neither nil nor empty.
} else {
// keyText.text or messageText.text are either nil or empty
}
如果您对iOS的快速编程和制作应用程序感兴趣,建议您进一步了解如何快速处理optional
和隐式展开的可选内容。一个开始的地方是https://docs.swift.org/swift-book/LanguageGuide/TheBasics.html,然后继续学习教程。