java中是否有命令来测量执行时间?
像
这样的东西System.out.println(execution.time);
在代码的末尾。
答案 0 :(得分:7)
以下是关于如何做到这一点的complete and little modified example:
public class ExecutionTimer {
private long start;
private long end;
public ExecutionTimer() {
reset();
start = System.currentTimeMillis();
}
public void end() {
end = System.currentTimeMillis();
}
public long duration(){
return (end-start);
}
public void reset() {
start = 0;
end = 0;
}
public static void main(String s[]) {
// simple example
ExecutionTimer t = new ExecutionTimer();
for (int i = 0; i < 80; i++){
System.out.print(".");
}
t.end();
System.out.println("\n" + t.duration() + " ms");
}
}
答案 1 :(得分:3)
您可以使用System.currentTimeMillis()
轻松自行实现:
final long start = System.currentTimeMillis();
executeLongRunningTask();
final long durationInMilliseconds = System.currentTimeMillis()-start;
System.out.println("executeLongRunningTask() took " + durationInMilliseconds + "ms.");
或者(特别是如果您的任务运行时间不长),您可能希望使用System.nanoTime()
。请注意,与currentTimeMillis()
的工作方式相反,nanoTime()
返回的值相对于某个指定时间不。这意味着nanoTime()
只能用于衡量时间跨度,不能用于识别某些特定时间点。
答案 2 :(得分:2)
您可以运行探查器,或使用两次调用System.currentTimeMillis()
像这样:
long start = System.currentTimeMillis();
....
doSomething();
....
long end = System.currentTimeMillis();
System.out.println("Execution time was "+(end-start)+" ms.");
答案 3 :(得分:2)
最简单的方法是在代码执行之前和之后使用System.currentTimeMillis()。 Joda-Time有更复杂的版本:http://joda-time.sourceforge.net/
答案 4 :(得分:1)
如果您想了解有关测量内容的更多详细信息,我强烈建议您使用JMX,尤其是ThreadMXBean:http://download.oracle.com/javase/6/docs/api/java/lang/management/ThreadMXBean.html
代码示例:
ThreadMXBean bean = ManagementFactory.getThreadMXBean( );
if (bean.isCurrentThreadCpuTimeSupported()) {
long cpuTime = bean.getCurrentThreadCpuTime( );
}
long userTime = bean.getCurrentThreadUserTime( );
此处提供了代码示例的完整解释: http://nadeausoftware.com/articles/2008/03/java_tip_how_get_cpu_and_user_time_benchmarking
答案 5 :(得分:1)
使用ThreadMXBean进行更详细的计时:
public class Timer {
static {
// needed to request 1ms timer interrupt period
// http://discuss.joelonsoftware.com/default.asp?joel.3.642646.9
Thread thread = new Thread(new Runnable() {
@Override
public void run() {
try {
Thread.sleep(Integer.MAX_VALUE); (Windows NT)
} catch (InterruptedException ignored) {
}
}
});
thread.setName("Timer");
thread.setDaemon(true);
thread.start();
}
private final ThreadMXBean threadMX = ManagementFactory.getThreadMXBean();
private final long elapsedStart;
private final long cpuStart;
private final long userStart;
public Timer() {
cpuStart = threadMX.getCurrentThreadCpuTime();
userStart = threadMX.getCurrentThreadUserTime();
elapsedStart = System.nanoTime();
}
public void times() {
long elapsed = elapsedStart - System.nanoTime();
long cpu = cpuStart - threadMX.getCurrentThreadCpuTime();
long user = userStart - threadMX.getCurrentThreadUserTime();
System.out.printf("elapsed=%-8.3f cpu=%-8.3f user=%-8.3f [seconds]",
elapsed/1.0e9, cpu/1.0e9, user/1.0e9);
}
}
答案 6 :(得分:1)
答案 7 :(得分:0)
您可以设计一个控件抽象time
,它将参数作为要执行的操作,并测量并打印执行它所需的时间。
<强>代码:强>
interface Action<A> {
public A perform();
}
class Timer {
public static <A> A time(final String description, final Action<A> action) {
final long start = System.nanoTime();
final A result = action.perform();
final long end = System.nanoTime();
System.out.println(description + " - Time elapsed: " + (end - start) +"ns");
return result;
}
}
class Main {
public static void main(final String[] args) {
final int factorialOf5 = Timer.time("Calculating factorial of 5",
new Action<Integer>() {
public Integer perform() {
int result = 1;
for(int i = 2; i <= 5; i++) {
result *= i;
}
return result;
}
}
);
System.out.println("Result: " + factorialOf5);
}
}
// Output:
// Calculating factorial of 5 - Time elapsed: 782052ns
// Result: 120
答案 8 :(得分:0)
我喜欢RoflcoptrException的类示例。 我重写了它的基本要点:
public class ExecutionTimer {
private long start;
public ExecutionTimer() {
restart();
}
public void restart() {
start = System.currentTimeMillis();
}
public long time(){
long end = System.currentTimeMillis();
return (end-start);
}
public String toString() {
return "Time="+time()+" ms";
}
}