我一直在找回错误代码:18,尝试使用Web Worker时来自Edge和Safari的SecurityError。但是,在Firefox / Chrome中,工作人员很好。我正在使用一个内联工作程序,我将零依赖数据处理函数传递给了该工作程序。
我的CSP看上去:
add_header Content-Security-Policy "default-src 'self'; worker-src 'self' 'inline' *.example.com";
我可以自己添加其他样式,例如本地样式表和googleapis.com,但我很好奇如何使Worker不会引发安全错误
来自worker method的片段
// Create an "inline" worker (1:1 at definition time)
const worker = new Worker(
// Use a data URI for the worker's src. It inlines the target function and an RPC handler:
'data:,$$='+asyncFunction+';onmessage='+(e => {
/* global $$ */
// Invoking within then() captures exceptions in the supplied async function as rejections
Promise.resolve(e.data[1]).then(
v => $$.apply($$, v)
).then(
// success handler - callback(id, SUCCESS(0), result)
// if `d` is transferable transfer zero-copy
d => {
postMessage([e.data[0], 0, d], [d].filter(x => (
(x instanceof ArrayBuffer) ||
(x instanceof MessagePort) ||
(x instanceof ImageBitmap)
)));
},
// error handler - callback(id, ERROR(1), error)
er => { postMessage([e.data[0], 1, '' + er]); }
);
})
);
Edge为工作程序抛出此错误:
[object DOMException]: {code: 18, message: "SecurityError", name:
"SecurityError"}
code: 18
message: "SecurityError"
name: "SecurityError"
答案 0 :(得分:1)
我不确定为什么数据url导致安全错误,但是您可以使用URL.createObjectURL
加载工作脚本,该脚本在Edge中似乎可以正常工作(我没有在野生动物园中对其进行测试)。
这里是这样的:
// Create the worker script as a string
const script = '$$='+asyncFunction+';onmessage='+(e => {
/* global $$ */
// Invoking within then() captures exceptions in the supplied async function as rejections
Promise.resolve(e.data[1]).then(
v => $$.apply($$, v)
).then(
// success handler - callback(id, SUCCESS(0), result)
// if `d` is transferable transfer zero-copy
d => {
postMessage([e.data[0], 0, d], [d].filter(x => (
(x instanceof ArrayBuffer) ||
(x instanceof MessagePort) ||
(x instanceof ImageBitmap)
)));
},
// error handler - callback(id, ERROR(1), error)
er => { postMessage([e.data[0], 1, '' + er]); }
);
});
// Create a local url to load the worker
const blob = new Blob([script]);
const workerUrl = URL.createObjectURL(blob);
const worker = new Worker(workerUrl);
让我知道您是否需要任何澄清!