我知道这可能很愚蠢,但所有旧案例都对我无效。而且都不是“ CAST”方法。
我正在尝试运行以下查询,但出现以下错误:
SELECT
P.date,
P.campaign_id,
P.ad_name,
P.impressions,
P.clicks,
P.spend,
P.NOM_ENSEMBLE,
P.CODE_ENSEMBLE_IMMO,
F.FREQUENTATION_CENTRE
FROM
`project.digital.fb_data` AS P
JOIN
`project.digital.freq_data` AS F
ON
(P.date = F.JOUR AND P.CODE_ENSEMBLE_IMMO=F.CODE_ENSEMBLE_IMMO)
错误:
Error: No matching signature for operator = for argument types: DATE, STRING. Supported signatures: ANY = ANY at [16:4]
答案 0 :(得分:1)
以下是用于BigQuery标准SQL
第一个查询是简化的查询,可重现/演示您的问题
#standardSQL
WITH `project.digital.fb_data` AS (
SELECT DATE '2019-02-15' `date`, 1 CODE_ENSEMBLE_IMMO
), `project.digital.freq_data` AS (
SELECT '02-15-2019' JOUR, 1 CODE_ENSEMBLE_IMMO, 'zzz' FREQUENTATION_CENTRE
)
SELECT
P.date,
P.CODE_ENSEMBLE_IMMO,
F.FREQUENTATION_CENTRE
FROM `project.digital.fb_data` AS P
JOIN `project.digital.freq_data` AS F
ON P.date = F.JOUR
AND P.CODE_ENSEMBLE_IMMO=F.CODE_ENSEMBLE_IMMO
有结果
Error: No matching signature for operator = for argument types: DATE, STRING. Supported signatures: ANY = ANY at [13:4]
下面的查询演示了如何解决上述问题
#standardSQL
WITH `project.digital.fb_data` AS (
SELECT DATE '2019-02-15' `date`, 1 CODE_ENSEMBLE_IMMO
), `project.digital.freq_data` AS (
SELECT '02-15-2019' JOUR, 1 CODE_ENSEMBLE_IMMO, 'zzz' FREQUENTATION_CENTRE
)
SELECT
P.date,
P.CODE_ENSEMBLE_IMMO,
F.FREQUENTATION_CENTRE
FROM `project.digital.fb_data` AS P
JOIN `project.digital.freq_data` AS F
ON P.date = PARSE_DATE('%m-%d-%Y', F.JOUR)
AND P.CODE_ENSEMBLE_IMMO=F.CODE_ENSEMBLE_IMMO
有结果
Row date CODE_ENSEMBLE_IMMO FREQUENTATION_CENTRE
1 2019-02-15 1 zzz
注意:您可以将F.JOUR
的格式设置为与上述示例不同的格式-因此请检查PARSE_DATE函数以了解如何处理其他supported formats