我有一个json int
文件,其中包含以下内容:
{
"action.button.submit": "Submit"
"action.button.submitting": "Submitting"
"buttons.common.add": "Add"
"buttons.common.reset": "Reset"
"constants.bom.conditional.or.mandatory.conditional": "Conditional"
"constants.bom.conditional.or.mandatory.mandatory": "Mandatory"
}
{
action: {
button: {
submit: 'Submit'
submitting: 'Submitting'
}
},
buttons: {
common: {
add: 'Add',
reset: 'Reset'
}
},
constants: {
bom: {
conditional: {
or: {
mandatory:{
conditional: 'Conditional',
mandatory: 'Mandatory'
}
}
}
}
}
}
这是我所能得到的:
newData = {};
Object.keys(data).forEach(item => {
const splitData = item.split('.');
splitData.forEach((detail, index) => {
if(index === 0 && !newData[detail]) newData[detail] = {};
})
});
console.info(newData)
我想拿Input
使其看起来像output
答案 0 :(得分:1)
您可以在对象条目上使用一个forEach
循环,然后在.
上内部拆分每个键。之后,您可以在该键数组上使用reduce
方法来构建嵌套对象。
const obj = {
"action.button.submit": "Submit",
"action.button.submitting": "Submitting",
"buttons.common.add": "Add",
"buttons.common.reset": "Reset",
"constants.bom.conditional.or.mandatory.conditional": "Conditional",
"constants.bom.conditional.or.mandatory.mandatory": "Mandatory"
}
const res = {}
Object.entries(obj).forEach(([key, value]) => {
key.split('.').reduce((r, e, i, a) => {
return r[e] || (r[e] = (a[i + 1] ? {} : value))
}, res)
})
console.log(res)
使用Lodash,您可以通过_.set
方法执行此操作,该方法采用目标对象,嵌套键和值。
const obj = {"action.button.submit": "Submit","action.button.submitting": "Submitting","buttons.common.add": "Add","buttons.common.reset": "Reset","constants.bom.conditional.or.mandatory.conditional": "Conditional","constants.bom.conditional.or.mandatory.mandatory": "Mandatory"}
const res = {}
_.forEach(_.entries(obj), ([k, v]) => _.set(res, k, v))
console.log(res)
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.js"></script>
答案 1 :(得分:1)
您必须递归地遍历生成的对象:
function parse(obj) {
const root = {};
for(const [key, value] of Object.entries(obj)) {
const parts = key.split(".");
const parent = parts.slice(0, -1).reduce((acc, part) => acc[part] || (acc[part] = {}), root);
parent[parts.pop()] = value;
}
return root;
}