VSCode xDebug PHP API配置

时间:2019-02-15 13:57:47

标签: php api symfony visual-studio-code xdebug

嗨,我在使用VSCode配置xDebug时遇到问题,我正在使用OS X

launch.json

    {
        "name": "Listen for XDebug",
        "type": "php",
        "request": "launch",
        "port": 9000
    },
    {
        "name": "Launch currently open script",
        "type": "php",
        "request": "launch",
        "program": "${file}",
        "cwd": "${fileDirname}",
        "port": 9000,
    }

php.ini

[xDebug]
zend_extension="/usr/lib/php/extensions/no-debug-non-zts-20160303/xdebug.so"
xdebug.remote_enable=1
xdebug.remote_port=9000
xdebug.remote_connect_back=1
xdebug.idekey=SOMEKEY
xdebug.remote_autostart=1

php -v

PHP 7.1.23 (cli) (built: Nov  7 2018 18:20:35) ( NTS )
Copyright (c) 1997-2018 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2018 Zend Technologies
with Xdebug v2.5.5, Copyright (c) 2002-2017, by Derick Rethans

能帮我吗?

0 个答案:

没有答案