Question

目标：

目标是使用postgresql SQL查询查找房间价格不变的第一个和最后一个观察日期。

我们完全迷失了，因此任何指导将不胜感激。

创建示例：

CREATE TABLE table_prices
(
    pk int GENERATED BY DEFAULT AS IDENTITY PRIMARY KEY,
    room_id character varying(50) COLLATE pg_catalog."default",
    check_in date,
    price integer,
    observation_date date
)

插入数据：

insert into table_prices (room_id, check_in, price, observation_date) values
('1', '2019-05-01', 100, '2019-01-01'),
('1', '2019-05-01', 100, '2019-01-02'),
('1', '2019-05-01', 100, '2019-01-03'),
('1', '2019-05-01', 150, '2019-01-04'),
('1', '2019-05-01', 150, '2019-01-05'),
('1', '2019-05-01', 150, '2019-01-06'),
('1', '2019-05-01', 150, '2019-01-07'),
('1', '2019-05-01', 100, '2019-01-08'),
('1', '2019-05-01', 100, '2019-01-09'),
('2', '2019-05-01', 200, '2019-01-01'),
('2', '2019-05-01', 200, '2019-01-02'),
('2', '2019-05-01', 200, '2019-01-03'),
('2', '2019-05-01', 200, '2019-01-04'),
('2', '2019-05-01', 200, '2019-01-05'),
('2', '2019-05-01', 200, '2019-01-06'),
('2', '2019-05-01', 200, '2019-01-07'),
('2', '2019-05-01', 200, '2019-01-08'),
('2', '2019-05-01', 200, '2019-01-09')

预期结果：

    room_id, check_in, first_observation, last_observation, price
1, 2019-05-01, 2019-01-01, 2019-01-03, 100
1, 2019-05-01, 2019-01-04, 2019-01-07, 150
1, 2019-05-01, 2019-01-08, 2019-01-09, 100
2, 2019-05-01, 2019-01-01, 2019-01-09, 200

Answer 1

这是一个空白和孤岛的问题-您可以尝试使用row_number()

DEMO

select room_id, check_in,min(observation_date) first_observation,max(observation_date)
last_observation,price
from
(
select *,island=row_number() over(partition by room_id order by observation_date) - 
row_number() over(partition by room_id, price order by observation_date) 
from table_prices
)A group by room_id, check_in,island,price

输出：

room_id check_in            first_observation   last_observation    price
1       01/05/2019 00:00:00 01/01/2019 00:00:00 03/01/2019 00:00:00 100
1       01/05/2019 00:00:00 04/01/2019 00:00:00 07/01/2019 00:00:00 150
1       01/05/2019 00:00:00 08/01/2019 00:00:00 09/01/2019 00:00:00 100
2       01/05/2019 00:00:00 01/01/2019 00:00:00 09/01/2019 00:00:00 200

SQL：确定每个连续的几天内的第一个和最后一个日期

1 个答案: