Question

您好，同一个表有两个不同的查询，条件不同，但是我只想在查询2的右边带1列。

select a.company_code, a.fb_id, a.account_code, a.cost_center,
       Round(sum(case when a.drcr_flag = 'Cr' then -1* a.base_amount else a.base_amount end),2) ytd_base_current,
       Round(sum(case when b.drcr_flag = 'Cr' then -1* b.base_amount else b.base_amount end),2) ytd_base_Pervious
from scmdb..fbp_posted_trn_dtl (nolock) a, scmdb..fbp_posted_trn_dtl b
where a.company_code = 'b5'
and a.posting_date BETWEEN '2019-01-01' AND '2019-01-31' 
and b.company_code = 'b5'
and b.posting_date BETWEEN '2018-01-01' AND '2018-12-31'
group by  a.company_code, a.fb_id, a.account_code, a.cost_center

查询将永远执行。

Answer 1

使用显式连接而不是逗号分隔的连接

select a.company_code, a.fb_id, a.account_code, a.cost_center,
       Round(sum(case when a.drcr_flag = 'Cr' then -1* a.base_amount else a.base_amount end),2) ytd_base_current,
       Round(sum(case when b.drcr_flag = 'Cr' then -1* b.base_amount else b.base_amount end),2) ytd_base_Pervious
from scmdb..fbp_posted_trn_dtl a inner join scmdb..fbp_posted_trn_dtl b
on a.company_code = b.company_code 
where a.company_code ='b5'
and a.posting_date BETWEEN '2019-01-01' AND '2019-01-31' 
group by  a.company_code, a.fb_id, a.account_code, a.cost_center

Answer 2

尝试一下...

select a.company_code, a.fb_id, a.account_code, a.cost_center,
       Round(sum(case when a.drcr_flag = 'Cr' then -1* a.base_amount else a.base_amount end),2) ytd_base_current,
       Round(sum(case when b.drcr_flag = 'Cr' then -1* b.base_amount else b.base_amount end),2) ytd_base_Pervious
from scmdb..fbp_posted_trn_dtl (nolock) a
join scmdb..fbp_posted_trn_dtl b
    on a.company_code = b.company_code
    and a.fb_id = b.fb_id
    and a.account_code = b.account_code
    and a.cost_center = b.cost_center
where a.company_code = 'b5'
    and a.posting_date BETWEEN '2019-01-01' AND '2019-01-31' 
    and b.posting_date BETWEEN '2018-01-01' AND '2018-12-31'
group by  a.company_code, a.fb_id, a.account_code, a.cost_center

组合查询1和查询2的结果，其中查询2中只有一列

2 个答案: