Question

python服务器从android接收图像文件，并作为响应发送字符串“ OK”。 python服务器的源代码如下：

serverSocket = socket(AF_INET, SOCK_STREAM)

serverSocket.bind(ADDR)
print('bind')

serverSocket.listen(CLIENT_NUM)
print('listen')

while True:
print('waiting...')
try:
    connectionSocket, addr_info = serverSocket.accept()
    print('accept')
    print('--client information--')
    print(connectionSocket)

    img = open("./img.jpg", 'wb')
    while True:
        img_data = connectionSocket.recv(BUFSIZE)
        data = img_data
        if img_data:
            while img_data:
                print("receiving Img...")
                img_data = connectionSocket.recv(BUFSIZE)
                data += img_data
            else:
                break
    img_file = open("img.jpg", "wb")
    print("finish img recv")
    img_file.write(data)
    img_file.close()

    connectionSocket.send("OK".encode())
    connectionSocket.close()
    print('connection closed')

except KeyboardInterrupt:
    sys.exit(0)

android客户端将图像文件发送到python服务器，并从python服务器接收字符串“ OK”。 python服务器的源代码如下：

 public void run() {
    try {
        InetAddress serverAddr = InetAddress.getByName(serverIp);
        socket = new Socket(serverAddr, serverPort);
        try {
            dataOutput = new DataOutputStream(socket.getOutputStream());
            dataInput = new DataInputStream(new FileInputStream(img));

            byte[] buf = new byte[BUF_SIZE];
            int dataLen;
            while ((dataLen = dataInput.read(buf)) != -1) {
                dataOutput.write(buf, 0, dataLen);
                dataOutput.flush();
            }
            BufferedReader reader = new BufferedReader(new InputStreamReader(socket.getInputStream()));
            Log.d("Socket", reader.readLine());
        } catch (Exception e) {
            StringWriter sw = new StringWriter();
            e.printStackTrace(new PrintWriter(sw));
            String exceptionAsString = sw.toString();
            Log.e("StackTrace", exceptionAsString);
        } finally {
            try {
                if (dataInput != null)
                    dataInput.close();
                if (dataOutput != null)
                    dataOutput.close();
                if (socket != null)
                    socket.close();
            } catch (IOException e) {
                StringWriter sw = new StringWriter();
                e.printStackTrace(new PrintWriter(sw));
                String exceptionAsString = sw.toString();
                Log.e("StackTrace", exceptionAsString);
            }
        }
    } catch (IOException e) {
        StringWriter sw = new StringWriter();
        e.printStackTrace(new PrintWriter(sw));
        String exceptionAsString = sw.toString();
        Log.e("StackTrace", exceptionAsString);
    }

}

服务器无法

如果删除下面两行，则服务器正常接收文件。但是，如果我在下面插入两行，则服务器不会收到该文件。

BufferedReader reader = new BufferedReader(new InputStreamReader(socket.getInputStream()));
Log.d("Socket", reader.readLine());

Android客户端如何将图像文件发送到python服务器并获得响应？

Answer 1

我解决了这个问题。我以为这个问题的原因一定是在服务器端，所以我修改了服务器的代码，它起作用了！

img = open("./img.jpg", 'wb')
img_data = connectionSocket.recv(BUFSIZE)
data = img_data
firstPacketLen = len(img_data)
print("receiving Img...")
while len(img_data) > 0:
    img_data = connectionSocket.recv(BUFSIZE)
    data += img_data
    if len(img_data) < firstPacketLen:
        break
print("finish img recv")
img.write(data)
img.close()

connectionSocket.send("OK\r\n".encode())
connectionSocket.shutdown(SHUT_RDWR)
connectionSocket.close()
print('connection closed')

android客户端无法收到python服务器的响应

1 个答案: