Question

这是我的代码：

Checking = open ("ReadDMI_Out.txt", "rt")
Result = open ("Result.txt", "a")
Fixed = ["T6", "J6", "K6", "N6"]

for line in Checking.readlines():
    if (Fixed ["T6", "J6", "K6", "N6"]) in line:
        Result.write("1")

    else:
         print ("0")

Answer 1

使用re，这就是您正在寻找的简单明了的内容。

import re

infile, outfile = "ReadDMI_Out.txt", "Result.txt"
fixed = ["T6", "J6", "K6", "N6"]
pattern = re.compile('|'.join(fixed))

with open(infile, 'r') as checking:
    with open(outfile, 'w') as result:
        for line in checking:
            result.write(str(int(pattern.search(line))))

还修正了您的空缺情况。您需要关闭它们，除非您使用with open(...) as ...:作为上下文管理器在完成后自动关闭文件。

此外，您知道您的结果文件中将只有一堆1吗？您可能需要某种分隔符...

Answer 2

您似乎想知道（尽管并不完全清楚）文件中的行何时包含["T6", "J6", "K6", "N6"]中的任何值。

将您的if测试更改为

if any(f in line for f in Fixed):

如何使用Python检查文本文件中数组是否存在

2 个答案: