Question

我想使用Python和opencv从多个视频长度中提取恒定数量的帧'n'。如何在Python中使用opencv？

例如在5秒的视频中，我想从该视频中平均提取10帧。

Answer 1

采用的代码来自：How to turn a video into numpy array?

import numpy as np
import cv2

cap = cv2.VideoCapture('sample.mp4')
frameCount = 10
frameWidth = int(cap.get(cv2.CAP_PROP_FRAME_WIDTH))
frameHeight = int(cap.get(cv2.CAP_PROP_FRAME_HEIGHT))

buf = np.empty((frameCount, frameHeight, frameWidth, 3), np.dtype('uint8'))

fc = 0
ret = True

while (fc < frameCount  and ret):
    ret, buf[fc] = cap.read()
    fc += 1

cap.release()
print(buf.shape) # (10, 540, 960, 3)

Answer 2

您可以获得帧的总数，将其除以n可得到每一步要跳过的帧数，然后读取帧数

    vidcap = cv2.VideoCapture(video_path)
    total_frames = vidcap.get(cv2.CAP_PROP_FRAME_COUNT)
    frames_step = total_frames//n
    for i in range(n):
        #here, we set the parameter 1 which is the frame number to the frame (i*frames_step)
        vidcap.set(1,i*frames_step)
        success,image = vidcap.read()  
        #save your image
        cv2.imwrite(path,image)
    vidcap.release()

Answer 3

您可以尝试使用此功能：

def rescaleFrame(inputBatch, scaleFactor = 50):
    ''' returns constant frames for any length video 
        scaleFactor: number of constant frames to get.  
        inputBatch : frames present in the video. 
    '''
    if len(inputBatch) < 1:
        return
    """ This is to rescale the frames to specific length considering almost all the data in the batch  """ 
    skipFactor = len(inputBatch)//scaleFactor
    return [inputBatch[i] for i in range(0, len(inputBatch), skipFactor)][:scaleFactor]

''' read the frames from the video '''
frames = []
cap = cv2.VideoCapture('sample.mp4')
ret, frame = cap.read()
while True:
   if not ret:
       print('no frames')
       break
   
   ret, frame = cap.read()
   frames.append(frame)

''' to get the constant frames from varying number of frames, call the rescaleFrame() function '''
outputFrames = rescaleFrames(inputBatch=frames, scaleFactor = 45)

输出：这将返回45帧作为恒定输出。

Python：以不同长度的视频提取“ n”帧

3 个答案: