Question

我正在使用CodeIgniter。我有两个表，我要加入，而不是使用加入。

成员

 member_id | name  | email       
        1  |lkjh   |asd@gmail.com
        2  |jjlk   |qwe@gmail.com
        3  |sfsd   |gfh@gmail.com
        4  |qqwe   |tyut@gmail.com

member_details

id | member_id |game   | year     | date_of_added
1  |   1       |lkjh   |2018-2019 | 14-02-2019 02:26:30
2  |   1       |jjlk   |2019-2020 | 14-02-2019 03:30:20
3  |   2       |sfsd   |2018-2019 | 14-02-2019 04:00:40
4  |   3       |qqwe   |2018-2019 | 14-02-2019 04:30:20
5  |   2       |sfsd   |2019-2020 | 14-02-2019 05:45:30

现在，我的问题是，我必须显示member_details中的所有记录，但是我必须显示member_id的最后一条记录。

所以我对member_details表的预期输出是

   1   |jjlk   |2019-2020 | 14-02-2019 03:30:20
   3   |qqwe   |2018-2019 | 14-02-2019 04:30:20
   2   |sfsd   |2019-2020 | 14-02-2019 05:45:30

我尝试了以下代码

$get_s_member = array('members.is_Approved'=>1,'members.is_status'=>1);
    $this->db->select('*');
    $this->db->from('members'); 
    $this->db->join('membership_details', 'members.member_id = membership_details.member_id','LEFT');
    $this->db->where($get_s_member);
    $this->db->group_by('membership_details.member_id'); 
    $this->db->order_by('membership_details.date_of_added','DESC');
     $this->db->limit('1');
    $query = $this->db->get();
    $res   = $query->result();
 return $res;

Answer 1

select t1.*, t2.* from 
member_details t1
join member 
on t1.member_id = t2.member_id
where (t1.member_id, t1.date_of_added) in
      (select member_id, max(date_of_added)
       from member_details
       group by member_id
      )

Answer 2

尝试一下

$get_s_member = array('members.is_Approved'=>1,'members.is_status'=>1);
$this->db->select('*');
$this->db->from('membership_details'); 
$this->db->join('members', 'membership_details.member_id = members.member_id','LEFT');
$this->db->where($get_s_member);
$this->db->group_by('membership_details.member_id'); 
$this->db->order_by('membership_details.date_of_added','DESC');
$query = $this->db->get();
$res   = $query->result();
return $res;

如何显示带有剩余记录的表中的最后一条记录？

2 个答案: