挂在视图方法

Question

我最近通过一门课程学习python。除非我使用view方法，否则一切都会顺利进行。有人也有这个问题吗？

我什至在https://pythonhosted.org/scikit-fuzzy/auto_examples/plot_tipping_problem_newapi.html#example-plot-tipping-problem-newapi-py中使用了示例代码。 （链接已更新）

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每当我查看查询部分时，我得到的只是一个小方框，该方框应向我显示图形，但它仍在继续加载。任何意见是极大的赞赏。谢谢！

Answer 1

这是运行的完整示例：

import matplotlib.pyplot as plt
import numpy as np
import skfuzzy as fuzz
from skfuzzy import control as ctrl

quality = ctrl.Antecedent(np.arange(0, 11, 1), 'quality')
service = ctrl.Antecedent(np.arange(0, 11, 1), 'service')
tip = ctrl.Consequent(np.arange(0, 26, 1), 'tip')

quality.automf(3)
service.automf(3)

tip['low'] = fuzz.trimf(tip.universe, [0, 0, 13])
tip['medium'] = fuzz.trimf(tip.universe, [0, 13, 25])
tip['high'] = fuzz.trimf(tip.universe, [13, 25, 25])

这是我的问题

quality['average'].view()


service.view()

tip.view()

rule1 = ctrl.Rule(quality['poor'] | service['poor'], tip['low'])
rule2 = ctrl.Rule(service['average'], tip['medium'])
rule3 = ctrl.Rule(service['good'] | quality['good'], tip['high'])

rule1.view()

tipping_ctrl = ctrl.ControlSystem([rule1, rule2, rule3])

tipping = ctrl.ControlSystemSimulation(tipping_ctrl)

使用带有Pythonic API的前标签将输入传递到ControlSystem

# Note: if you like passing many inputs all at once, use .inputs(dict_of_data)
tipping.input['quality'] = 6.5
tipping.input['service'] = 9.8

# Crunch the numbers
tipping.compute()
print (tip)
tip.view(sim=tipping)

plt.show()

Answer 2

由于skfuzzy使用matplotlib和NetworkX的内幕，因此您可以尝试使用以下代码来显示您的身材：

import matplotlib.pyplot as plt
import numpy as np
import skfuzzy as fuzz
from skfuzzy import control as ctrl

quality = ctrl.Antecedent(np.arange(0, 11, 1), 'quality')
service = ctrl.Antecedent(np.arange(0, 11, 1), 'service')
tip = ctrl.Consequent(np.arange(0, 26, 1), 'tip')

quality.automf(3)
service.automf(3)

tip['low'] = fuzz.trimf(tip.universe, [0, 0, 13])
tip['medium'] = fuzz.trimf(tip.universe, [0, 13, 25])
tip['high'] = fuzz.trimf(tip.universe, [13, 25, 25])

# HERE COMES MY PROBLEM
quality['average'].view()

plt.show()