Question

我已经为此工作了一段时间。我已经能够使其中的一部分起作用，但没有全部起作用。最终目标是在用户选择的情况下将其循环回另一个游戏。我认为问题出在我的break语句上，但是我不确定如何解决它。我已经包含了所有代码，以便可以发现任何错误。抱歉，如果已解决此问题，我找不到与此类问题有关的页面。

def game():
    import random
    from random import randint
    n = randint(1, 10)
    print('Enter a seed vlaue: ')
    the_seed_value = input(' ')

    random.seed(the_seed_value)

    guessesTaken = 0

    print("what is your name?")
    myName = input("")

    guess = int(input("Enter an integer from 1 to 99: "))

    while n != "guess":


        if guess < n:
            print ("guess is low")
            guessesTaken = guessesTaken + 1
            guess = int(input("Enter an integer from 1 to 99: "))
        elif guess > n:
            print ("guess is high")
            guessesTaken = guessesTaken + 1
            guess = int(input("Enter an integer from 1 to 99: "))
        else:
            print ("Congradulations " + myName +  " you guessed it in " + str(guessesTaken) + " guesses!") 
            break 


    print('Want to play agian? y/n')
    answer = input(" ")
    if answer == "n":
        print ("Ok, See you next time!")

    elif answer == "y":
        print("Starting new game!")
        game()


def main():
    game()

if __name__ == "__main__":
    main()

Answer 1

例如，@ kerwei正确地指出您的while行存在问题，需要将其从while n != "guess":更改为while n != guess:。

对于两个玩家，当玩家正确猜测时，绕过Congrats行即可满足您的while循环。

由于游戏目前的结构是一直处于循环状态，直到玩家正确猜出为止，一个简单的解决方法是从循环中删除else:行，然后放置胜利声明。也就是说，

def game()
    ...
    while n != guess:
        if guess < n:
            ...
        elif guess > n:
            ...
    print('Congrats!')
    print('play again?')
    ...

打破基本python的循环

1 个答案: