Question

我有两张桌子。

Sales
------

ID    Charge    VAT
1     100      10
2     200      20


SaleProducts
------------

ID  Product    Auto   SalesID
1   aa         True   1 
2   bb         False  1

我想得到这个

SaleOnProduct
-------------

ID    Product     Charge     VAT    Total   TotalAmount(All of total is plus)
1     aa          100        10     110     220  
2     aa          100        10     110     220

我该怎么做？请帮帮我。

Answer 1

declare @Sales table (ID int, Charge int, VAT int)
declare @SaleProducts table (ID int, Product char(2), Auto bit, SalesID int)

insert into @Sales values
(1, 100, 10),
(2, 200, 20)

insert into @SaleProducts values
(1, 'aa', 1, 1),
(2, 'bb', 0, 1)

select 
  SP.ID, 
  SP.Product,
  S.Charge,
  S.VAT,
  S.Charge+S.VAT as Total,
  sum(S.Charge+S.VAT) over() as TotalAmount
from @Sales as S
  inner join @SaleProducts as SP
    on S.ID = SP.SalesID

Answer 2

为了从同一结果集中的两个表中获取数据，您需要进行连接。

由于您希望每个特定产品的所有销售（（费用+增值税）* numberofSaleProductsRows）都有一个汇总行，您需要使用SUM聚合函数和GROUP BY子句。结果集中需要的所有列以及没有指定聚合的列都需要包含在GROUP BY列表中。

免责声明：未经测试的代码

 SELECT ID, Product, Charge ,VAT, Charge + VAT as Total, 
            Sum(Charge + VAT) as TotalAmount
 FROM Sales INNER JOIN SaleProducts 
           ON Sales.ID = SaleProducts.SalesID
 GROUP BY ID, Product, Charge, VAT, Charge + VAT

Answer 3

此查询执行以下任务:(我认为SQL Server 2005或更高版本，否则您需要通过临时表更改cte）

WITH ReportCte as(
SELECT  b.Id IdSale,
        a.Id IdProduct,
        a.Product,
        b.Charge,
        b.VAT,
        b.Charge+b.VAT Total
  FROM  [dbo].[SaleProducts] a left join
        [dbo].[Sales] b on a.[SalesID] = b.ID)
SELECT  a.IdProduct,
        a.IdProduct,
        a.Charge,
        a.VAT,
        a.Total,
        b.TotalAmount
FROM    ReportCte a left join
        (select IdSale,SUM(Total) TotalAmount 
        from ReportCte group by IdSale) b on a.IdSale=b.IdSale

Answer 4

select *, (charge+VAT) as total, SUM(charge+VAT) as totalAmount
from sales
join saleproducts on sales.ID=saleproducts.salesID
group by sales.ID

如何获得总和

4 个答案: