Question

我有适用于一个指定文件的代码。如何为多个文件迭代相同的功能？

以下代码适用于test3.txt文件。我在一个文件夹中有多个文件（test1.txt，test2.txt，test3.txt ...），能否请您帮我遍历每个文件？我相信我必须更改第6-7行。请帮忙。我是python的新手...

import os,csv,datefinder,re
import numpy as np

os.chdir('C:\Users\dul\Dropbox\Article')

with open("test3.txt", 'r') as file1:
      text1=file1.read()

#locate the date of the article
matches = list(datefinder.find_dates(text1))

if len(matches) > 0:
    date=matches[1]
    strdate = str(date)

else:
    print 'No dates found'


#locate the name of the company
matchcomp = re.search(r'Keywords:([^,]*)(,|$)', text1).group(1).strip()

#count the number of words in the article
matchcount = re.search(r'(.*) words', text1).group(1).strip()

#determine the article
def matchwho():
    if 'This story was generated by' in text1:
        return('1')
    elif 'This story includes elements generated' in text1:
        return('2')
    elif 'Elements of this story were generated' in text1:
        return('2')
    elif 'Portions of this story were generated' in text1:
        return('2')
    else:
        return('3')

matchw =str(matchwho())

#list the returns in a line
combid = matchcomp + "," + strdate + "," + matchw + "," + matchcount

#save in txt format
with open('outfile.txt', 'w') as outfile:
    outfile.write(combid)

我希望收益会附加在outfile.txt中

Answer 1

首先将第6行中的所有内容移至名为process_file的新函数中，该函数将获得参数filename，然后将该函数中的text3.txt替换为filename < / p>

现在您可以在脚本结尾处编写

for f in os.listdir('C:\Users\dul\Dropbox\Article'):
    process_file(f)

这将完成工作。

Answer 2

如何将所有代码打包到一个可以为每个文件多次调用的函数中

import os,csv,datefinder,re
import numpy as np

os.chdir('C:\Users\dul\Dropbox\Article')

def matchwho(text_to_match):
    if 'This story was generated by' in text_to_match:
        return('1')
    elif 'This story includes elements generated' in text_to_match:
        return('2')
    elif 'Elements of this story were generated' in text_to_match:
        return('2')
    elif 'Portions of this story were generated' in text_to_match:
        return('2')
    else:
        return('3')


def extract_data(filename):
    with open(filename, 'r') as file1:
        text1=file1.read()
    #locate the date of the article
    matches = list(datefinder.find_dates(text1))
    if len(matches) > 0:
        date=matches[1]
        strdate = str(date)
    else:
        print 'No dates found'
    #locate the name of the company
    matchcomp = re.search(r'Keywords:([^,]*)(,|$)', text1).group(1).strip()
    #count the number of words in the article
    matchcount = re.search(r'(.*) words', text1).group(1).strip()
    #determine the article
    matchw =str(matchwho(text1))
    #list the returns in a line
    combid = matchcomp + "," + strdate + "," + matchw + "," + matchcount
    #save in txt format
    with open('outfile.txt', 'w') as outfile:
        outfile.write(combid)

files = os.listdir()
for file in files:
    if ".txt" in file:
        extract_data(file)

*注意，我没有测试此代码，因为我没有正在处理的.txt文件。可能有错误，但是我认为它展示了如何获取文件名并将其输入处理功能。如果这样可以解决您的问题，那么可以单击帖子旁的复选标记：）

如何遍历目录中的每个文件的功能

2 个答案: