Question

我正在构建一个WPF应用程序，该应用程序使用套接字在服务器之间来回传输数据。问题：从服务器发送和接收数据时，屏幕被冻结，我想添加一个简单的加载动画，以便最终用户可以知道它当前正在加载，但是我不知道如何

我的C＃套接字代码：

<?php
namespace Solarium;
use Solarium;
require 'vendor/autoload.php';
require(__DIR__.'\solarium\init.php');

htmlHeader();

// check solarium version available
echo 'Solarium library version: ' . Client::VERSION . ' - ';

// create a client instance

$config = array(
    'endpoint' => array(
        'localhost' => array(
            'host' => 'localhost',
            'port' => 3306,
            'path' => '/solarium/',
        )
    )
);

$client = new Solarium\Client($config);

// create a ping query
$ping = $client->createPing();

// execute the ping query
try {
    $result = $client->ping($ping);
    echo 'Ping query successful';
    echo '<br/><pre>';
    var_dump($result->getData());
    echo '</pre>';
} catch (Solarium\Exception $e) {
    echo 'Ping query failed';
}

htmlFooter();

，然后在窗口中按一个名为“ login.xaml”的按钮，然后在检查数据正常后，调用它，它关闭当前窗口并初始化dashboard.xaml。与服务器通信时，我只需要添加动画即可。

谢谢！

Answer 1

在后台线程上调用SendRecOne方法，或通过使用* Async重载使其异步：

public static async Task<string> SendRecOne(string dataToSvr)
{
    progressBar.Visibility = Visibility.Visible;
    string ToReturn = null;
    using (TcpClient client = new TcpClient(SERVER_NAME, PORT))
    {
        int ByteCount = Encoding.ASCII.GetByteCount(dataToSvr); //How much bytes?
        byte[] ByteBuffer = new byte[1024]; //initialize byte array
        ByteBuffer = Encoding.ASCII.GetBytes(dataToSvr);
        NetworkStream stream = client.GetStream();
        await stream.WriteAsync(ByteBuffer, 0, ByteBuffer.Length);

        //byte[] responseData = new byte[client.ReceiveBufferSize];
        //int bytesRead = await stream.ReadAsync(responseData, 0, client.ReceiveBufferSize);
        int i;
        ByteBuffer = new byte[ByteBuffer.Length];
        MemoryStream ms = new MemoryStream();
        if (stream.DataAvailable)
        {
            while ((i = await stream.ReadAsync(ByteBuffer, 0, ByteBuffer.Length)) != 0)
            {
                await ms.WriteAsync(ByteBuffer, 0, ByteBuffer.Length);
                if (!stream.DataAvailable)
                    break;
            }
            ToReturn = Encoding.ASCII.GetString(ms.ToArray());
        }
        progressBar.Visibility = Visibility.Collapsed;
    }
    return ToReturn;
}

XAML：

<ProgressBar x:Name="progressBar" IsIndeterminate="True" />

UI线程无法同时处理消息和执行代码。

C＃WPF在套接字发送和接收数据时显示加载屏幕C＃

1 个答案: