Question

我想读取json属性值，我的json格式就像这样

{"content":{"@attributes" : { "start_limit" : "x","end_limit" : "x","total_records" : "x"},"item":[{"category":"x","distance":"x"}]}},

我想从json属性中读取total_record的值。我怎么读？请帮帮我

由于约翰里克

Answer 1

首先检查你的JSON String.Change it to

来自

的

{"content":{"@attributes" : { "start_limit" :"x","end_limit" : "x","total_records" : "x"}},"item":[{"category":"x","distance':"x"}]}}

{"content":{"@attributes" : { "start_limit" : "x","end_limit" : "x","total_records" : "x"},"item":[{"category":"x","distance":"x"}]}}

你在“item”之前留下一个结束大括号。

现在，下面是获取“total_records”值的代码

String jsonString = "{'content':{'@attributes' : { 'start_limit' :'x','end_limit' : 'x','total_records' : 'x'}},'item':[{'category':'x','distance':'x'}]}}";

public String getTotalRecords(String jsonString){
    try {
            JSONObject mainObject = new JSONObject(jsonString);
            JSONObject contentObject = mainObject.getJSONObject("content");
            JSONObject attributesObject = contentObject.getJSONObject("@attributes");
            String totalRecords = attributesObject.getString("total_records");
            Log.i("Total Records", totalRecords);
        } catch (JSONException e) {
            e.printStackTrace();
        }
    return totalRecords;
}

希望你能理解这个问题。

Answer 2

只需使用JSONObject。

JSONObject obj = new JSONObject(src);
String totalRecs = obj.getString("total_records");

不是100％确定它有效，但它是一个很好的例子从哪里开始。

Answer 3

希望你在问过之前已经试过了。如果没有，这里有几个网址（我用Google搜索）： http://www.androidcompetencycenter.com/2009/10/json-parsing-in-android/和http://about-android.blogspot.com/2010/03/androind-json-parser.html

如何使用android在json中读取属性值

3 个答案: