我在开发中使用blade.php
,因此在验证输入内容是否为有效的instagram网址时存在顾虑。我尝试这样做:
<form class="search_form" id="apply" action=" method="post">
@csrf
<label>
<input type="url" pattern="https?://.+" required id="instagram" value="" placeholder="Instagram Post URL (Paste Here)">
</label>
<div class="flex_box">
<button class="btn pink applyfnsh_btn" type="button" id="save">Confirm</button>
</div>
</form>
更新验证后将显示此模式
<div class="applyfnsh_modal">
<div class="applyfnsh_box">
<div class="modal_close">
<img src="../../assets/images/close.png" alt="close">
</div>
<p>Success</p>
</div>
</div>
modal.js
$(".applyfnsh_btn").on("click", function(){
$(".apply_modal").toggleClass("open");
$(".applyfnsh_modal").toggleClass("open");
});
$(".applyfnsh_modal").on('click touchend', function(event) {
if (!$(event.target).closest('.applyfnsh_box').length) {
$(".applyfnsh_modal").toggleClass("open");
$("body").toggleClass("open");
}
});
位置在这里
<script src="{{ url('/assets/js/modal.js') }}"></script>
顺便说一句,我正在使用ajax将数据保存到db,以便该页面不会刷新。
<script>
$(document).on("click", "#save", function() {
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
}
});
$.ajax({
type: "post",
url: '/contest/apply/{{ $contest->id }}',
data: {url : $("#instagram").val(), user_id: 1, contest_id: {{ $contest->id }} },
success: function(store) {
},
error: function() {
}
});
});
</script>
这不起作用,甚至在单击按钮时也处理数据,即使输入不是url或为空。 有没有做功能的方法吗?
答案 0 :(得分:1)
在这里:
$(document).on("click", "#save", function() {
var instagramLink = $('#instagramLink').val();
var pattern = new RegExp('https://www.instagram.com/p/(.+?)', 'g');
if((instagramLink != undefined || instagramLink != '') && instagramLink.match(pattern)){
alert(instagramLink + 'is valid');
/*
$.ajax({
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
},
type: "post",
url: '/contest/apply/{{ $contest->id }}',
data: {url :instagramLink, user_id: 1, contest_id: {{ $contest->id }} },
success: function(store) {
},
error: function() {
}
});
*/
}else{
alert('Please Enter Valid Instagram Link');
$('#instagramLink').val('');
// show modal
$('.applyfnsh_modal').modal('open');
}
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/css/bootstrap.min.css" integrity="sha384-ggOyR0iXCbMQv3Xipma34MD+dH/1fQ784/j6cY/iJTQUOhcWr7x9JvoRxT2MZw1T" crossorigin="anonymous">
<!doctype html>
<html lang="en">
<head>
<!-- Required meta tags -->
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1, shrink-to-fit=no">
<!-- Bootstrap CSS -->
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/css/bootstrap.min.css" integrity="sha384-ggOyR0iXCbMQv3Xipma34MD+dH/1fQ784/j6cY/iJTQUOhcWr7x9JvoRxT2MZw1T" crossorigin="anonymous">
<title>Hello, world!</title>
</head>
<body>
<form class="search_form" id="apply" action="" method="post">
<label>
<input type="url" required id="instagramLink" value="" placeholder="Instagram Post URL (Paste Here)" class="form-control"/>
</label>
<div class="flex_box">
<button class="btn btn-primary" type="button" id="save">Confirm</button>
</div>
</form>
</body>
</html>
update-2:删除现有脚本:
$(".applyfnsh_btn").on("click", function(){
$(".apply_modal").toggleClass("open");
$(".applyfnsh_modal").toggleClass("open");
});
$(".applyfnsh_modal").on('click touchend', function(event) {
if (!$(event.target).closest('.applyfnsh_box').length) {
$(".applyfnsh_modal").toggleClass("open");
$("body").toggleClass("open");
}
});
在需要显示时使用这种方式显示模式:
到OPEN MODAL:$('。applyfnsh_modal')。addClass('open');
关闭模式:$('。applyfnsh_modal')。removeClass('open');
如此
if (validation successfull){
// submit form using AJAX
}else{
$('.applyfnsh_modal').addClass('open');
}
还创建一个函数来关闭模式:
$(document).on('click','.modal_close',function(){
$('.applyfnsh_modal').removeClass('open');
});