Question

在我的Spring Boot应用程序中，我有一个带有用户定义的type out参数的oracle存储过程。当我使用以下代码调用该sp时，出现“ java.lang.IllegalArgumentException：类型不能为null”错误。

我应该如何处理这种输入？

JPA是否支持用户定义的类型参数？

SP：

create or replace PROCEDURE sp_sprintboot_test (

    pn_input1            IN     NUMBER,
    ps_input2            IN     VARCHAR2,
    pn_output1             OUT NUMBER,
    ps_output2             OUT VARCHAR2,
    pt_output3              OUT TYPE_SPRINGBOOT_TEST)
AS

BEGIN
    PN_OUTPUT1 := pn_input1 + 100;
    ps_output2 := 'Test deneme ' || PS_INPUT2;
    PT_OUTPUT3 := TYPE_SPRINGBOOT_TEST(247, 'Merkez');

END;

类型：

create or replace TYPE   type_springboot_test as object
(
 BRANCH NUMBER(5,0),
 NAME VARCHAR2(500)
)

代码：

@Repository
public class TestSPRepositoryImp implements TestSPRepository {

    @PersistenceContext
    private EntityManager entityManager;

    public String getTestData() {
        StoredProcedureQuery query = entityManager
                .createStoredProcedureQuery("sp_sprintboot_test")
                .registerStoredProcedureParameter(1, Long.class,
                        ParameterMode.IN)
                .registerStoredProcedureParameter(2, String.class,
                        ParameterMode.IN)
                .registerStoredProcedureParameter(3, Long.class,
                        ParameterMode.OUT)
                .registerStoredProcedureParameter(4, String.class,
                        ParameterMode.OUT)
                .registerStoredProcedureParameter(5, TYPE_SPRINGBOOT_TEST.class,
                        ParameterMode.OUT)
                .setParameter(1, 28L)
                .setParameter(2, "Test Input");

        query.execute();

        Long output1 = (Long)query.getOutputParameterValue(3);
        String output2 = (String)query.getOutputParameterValue(4);
        TYPE_SPRINGBOOT_TEST output3 = (TYPE_SPRINGBOOT_TEST)query.getOutputParameterValue(5);

        return "Output1 : " + output1 + " Output2 : " + output2 + " Output3 :" + output3;
    }
}



public class TYPE_SPRINGBOOT_TEST {
    Long BRANCH;
    String NAME;


    public Long getBRANCH() {
        return BRANCH;
    }

    public void setBRANCH(Long BRANCH) {
        this.BRANCH = BRANCH;
    }

    public String getNAME() {
        return NAME;
    }

    public void setNAME(String NAME) {
        this.NAME = NAME;
    }
}

Spring Boot-JPA-Hibernate-用户定义类型的存储过程调用

0 个答案: