我有一个名为sdb
的数据库,其中有3个表users
,posts
和users_follow
以下所有3个表的创建表查询
-- users table
CREATE TABLE `users` (
`user_id` int(11) NOT NULL AUTO_INCREMENT,
`uname` varchar(25) NOT NULL,
`email` varchar(35) NOT NULL,
`password` varchar(255) NOT NULL,
`user_status` enum('active','inactive','remove') DEFAULT 'active',
`signup_at` datetime DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`user_id`)
) ENGINE=InnoDB;
-- posts table
CREATE TABLE `posts` (
`post_id` int(11) NOT NULL AUTO_INCREMENT,
`title` tinytext NOT NULL,
`content` text NOT NULL,
`posted_at` datetime DEFAULT CURRENT_TIMESTAMP,
`user_id` int(11) DEFAULT NULL,
PRIMARY KEY (`post_id`),
KEY `posts_fk1` (`user_id`),
CONSTRAINT `posts_fk1` FOREIGN KEY (`user_id`) REFERENCES `users` (`user_id`) ON DELETE CASCADE ON UPDATE CASCADE
) ENGINE=InnoDB;
-- users_follow table
CREATE TABLE `users_follow` (
`follow_id` int(11) NOT NULL AUTO_INCREMENT,
`follower_id` int(11) DEFAULT NULL,
`following_id` int(11) NOT NULL,
`follow_status` enum('active','blocked') DEFAULT 'active',
PRIMARY KEY (`follow_id`),
KEY `users_follow_fk1` (`follower_id`),
KEY `users_follow_fk2` (`following_id`),
CONSTRAINT `users_follow_fk1` FOREIGN KEY (`follower_id`) REFERENCES `users` (`user_id`) ON DELETE CASCADE ON UPDATE CASCADE,
CONSTRAINT `users_follow_fk2` FOREIGN KEY (`following_id`) REFERENCES `users` (`user_id`) ON DELETE CASCADE ON UPDATE CASCADE
) ENGINE=InnoDB;
我尝试以下查询(对于user_id = 1的用户)
SELECT a.user_id,
SUM(CASE WHEN f.following_id = 1 THEN 1 ELSE 0 END) AS count_followers,
SUM(CASE WHEN f.follower_id = 1 THEN 1 ELSE 0 END) AS count_followings,
SUM(CASE WHEN p.user_id = 1 THEN 1 ELSE 0 END) AS count_posts
FROM users_follow f
RIGHT JOIN users a
ON f.following_id = a.user_id
RIGHT JOIN users b
ON f.follower_id = b.user_id
LEFT JOIN posts p
ON p.user_id = a.user_id
where a.user_id = 1;
以上查询返回count_posts
和count_followers
,count_following = 0
的相同计数
输出: output
答案 0 :(得分:1)
我想您可能需要遵循这些原则
select a.user_id,
(
select count(*)
from posts p
where a.user_id = p.user_id
) count_posts,
(
select count(*)
from users_follow f
where f.follower_id = a.user_id
) count_followings,
(
select count(*)
from users_follow f
where f.following_id = a.user_id
) count_followers
from users a
如果您想使用GROUP BY
和外部联接来编写它,则绝对需要使其成为内联子查询。因此,像这样
select a.user_id,
p.count_posts,
f1.count_followings,
f2.count_followers
from users a
left join (
select a.user_id, count(*)
from posts p
group by a.user_id
) p on p.user_id = a.user_id
left join
(
select f.follower_id, count(*) count_followings
from users_follow f
group by f.follower_id
) f2
left join f2.follower_id = a.user_id
(
select f.following_id, count(*) count_followers
from users_follow f
group by f.following_id
) f2 on f2.following_id = a.user_id
答案 1 :(得分:0)
implementation 'com.google.firebase:firebase-core:16.0.0'
implementation 'com.google.firebase:firebase-auth:16.0.1'
implementation 'com.google.firebase:firebase-messaging:17.0.0'
表的性能可以提高:
user_follow