如何在闭包内引用自身

Question

如果我有类似的结构

// In app.rs
pub struct App {
    pub foo: bar[],
    pub bar_index: i32,
    pub true_false: bool
}

impl App {
    pub fn access<F: Fn(&mut OtherStruct)> (&mut self, action: F) {
        if let OtherStruct(baz) = &mut self.foo[self.bar_index] {
            action(baz);
        }
    }
}

// In main.rs
// `app` is a mutable variable defined elsewhere
app.access(|baz| {
    if app.true_false {
        // do something
    });

运行此app.access会导致借阅检查器抛出拟合。我认为这是因为我在闭包中引用了app，但不确定如何解决它。有解决办法吗？

Answer 1

您可以将self作为参数传递给action：

impl App {
    pub fn access<F: Fn(&App, &mut OtherStruct)>(&mut self, action: F) {
        if let OtherStruct(baz) = &mut self.foo[self.bar_index] {
            action(&self, baz);
        }
    }
}

app.access(|app, baz| {
    if app.true_false {
        unimplemented!()
    }
});