Question

这应该是Python 3中的密码生成器程序。

import string
from random import *

print("Type Yes or No For The Following Questions:")

letters = raw_input("Do you want letters in your passcode?" )
if raw_input == 'Yes': chars1 = string.ascii_letters 
elif raw_input == 'No': chars1  = ""

digits = raw_input("Do you want digits in your passcode?" )
if raw_input == 'Yes':chars2 = string.digits
elif raw_input == 'No': chars2 = ""

symbols = raw_input("Do you want symbols in your passcode?" )
if raw_input == 'Yes': chars3 = string.punctuation 
elif raw_input == 'No': chars3  = ""

requestedlength = input("What passcode length do you want? Type any   number: ")
length = int(requestedlength)

chars = chars1 + chars2 + chars3

passcode = raw_input("Type Enter To Generate Random Passcode: ")
print("".join(choice(chars) for x in range((length))))

我在这里做错了什么？该错误指出未定义chars1 chars2和chars3。在条件语句中更改这些变量后，如何定义这些变量？我是Python的新手，如果代码混乱，我深表歉意：（

编辑：谢谢大家的回答！

Answer 1

因为您的if语句没有问正确的事情

您在输入中设置了一些变量

letters = raw_input("Do you want letters in your passcode?" )

然后询问raw input是否为“是”（从未如此）

if raw_input == 'Yes': chars1 = string.ascii_letters

所以您的if语句始终为false，并且变量（chars1等）永远都不会被设置，因此您会收到错误消息

要解决此问题，只需更改您的if语句

if letters == 'Yes': chars1 = string.ascii_letters

Answer 2

在其他循环中，将if语句中的“输入”拼写更改为“字母”等：

double

Answer 3

这就是我的工作方式：

import string
from random import *

print("Type Yes or No For The Following Questions:")

letters = input("Do you want letters in your passcode?" )
if letters == 'Yes': chars1 = string.ascii_letters 
elif letters == 'No': chars1  = ""

digits = input("Do you want digits in your passcode?" )
if digits == 'Yes':chars2 = string.digits
elif digits == 'No': chars2 = ""

symbols = input("Do you want symbols in your passcode?" )
if symbols == 'Yes': chars3 = string.punctuation 
elif symbols == 'No': chars3  = ""

requestedlength = input("What passcode length do you want? Type any   number: ")
length = int(requestedlength)

chars = chars1 + chars2 + chars3

passcode = input("Type Enter To Generate Random Passcode: ")
print("".join(choice(chars) for x in range((length))))

条件后未定义变量

3 个答案: