第一次尝试GraphQL,我希望一个Schema Type可以访问另一个Schema Type中的对象数组。在将其连接到MongoDB之前,我正在使用本地数据和lodash进行测试。我在尝试中遇到一些错误。我知道我要走了任何援助将不胜感激。
以下是我的最新尝试。我使用express-graphql访问了GraphQLList,并使用GraphQLID访问了第二个模式。
schema.js
var projects = [
{
name: "Title 1",
subtitle: "Subtitle 1",
summary: "Lorem ipsum....",
languageId: ["4", "2"],
id: "1"
},
...
var languages = [
{ name: "Javascript", id: "1" },
{ name: "HTML", id: "2" },
{ name: "CSS", id: "3" },
{ name: "Python", id: "4" },
]
...
const ProjectType = new GraphQLObjectType({
name: 'Project',
fields: () => ({
id: { type: GraphQLID },
name: { type: GraphQLString },
subtitle: { type: GraphQLString },
summary: { type: GraphQLString },
languages: {
type: new GraphQLList(GraphQLID),
resolve(parent, args) {
console.log(parent)
return _.find(languages, { id: parent.languageId })
}
}
})
});
const LanguageType = new GraphQLObjectType({
name: 'Language',
fields: () => ({
id: { type: GraphQLID },
name: { type: GraphQLString },
})
});
//Root Queries
const RootQuery = new GraphQLObjectType({
name: 'RootQueryType',
fields: {
project: {
type: ProjectType,
args: { id: { type: GraphQLID } },
resolve(parent, args) {
return _.find(projects, { id: args.id });
}
},
language: {
type: LanguageType,
args: { id: { type: GraphQLID } },
resolve(parent, args) {
return _.find(languages, { id: args.id })
}
}
}
});
目的是在Graphiql中显示该项目中使用的语言列表,看起来像这样...
{
"data": {
"project": {
"name": "Project 1"
languages{
names{
"Python"
"HTML"
}
}
}
}
}
相反,我得到以下信息...
{
"errors": [
{
"message": "Syntax Error: Expected Name, found }",
"locations": [
{
"line": 7,
"column": 7
}
]
}
]
}
我重新格式化了对多种语言进行硬编码的解决方法,虽然可以,但是没有功能。任何建议将不胜感激。谢谢大家的时间。
答案 0 :(得分:0)
我不确定您要查询哪个查询。
但是,为了返回嵌套在Languages
中的Projects
,您应该更改languages
字段的返回类型。
类似的东西:
const ProjectType = new GraphQLObjectType({
name: 'Project',
fields: () => ({
id: {type: GraphQLID},
name: {type: GraphQLString},
subtitle: {type: GraphQLString},
summary: {type: GraphQLString},
languages: {
// change this type to LanguageType
type: new GraphQLList(LanguageType),
resolve(parent, args) {
// No need to lodash here
return languages.filter((language) => {
return parent.languageId.includes(language.id)
})
}
}
})
});
答案 1 :(得分:0)
我的标签的旧项目有问题。最后,我通过尝试发现它,并抓住了你可以使用它 标签:{type:GraphQLList(GraphQLString)},