Question

python manage.py runserver引发异常。如何在本地主机上获取启动网页？

我尝试了Django Slack社区小组，还尝试了关于Django Framework中“ RecursionError”的StackOverflow问题，但答案不确定且令人困惑。

python3 manage.py运行服务器正在执行系统检查...

Unhandled exception in thread started by <function check_errors.<locals>.wrapper at 0x102b926a8>
Traceback (most recent call last):
File "/Users/kuldeep/env/lib/python3.7/site-packages/django/utils/autoreload.py", line 225, in wrapper fn(*args, **kwargs)
File "/Users/kuldeep/env/lib/python3.7/site-packages/django/core/management/commands/runserver.py", line 117, in inner_run            self.check(display_num_errors=True)
File "/Users/kuldeep/env/lib/python3.7/site-packages/django/core/management/base.py", line 379, in check
        include_deployment_checks=include_deployment_checks,
File "/Users/kuldeep/env/lib/python3.7/site-packages/django/core/management/base.py", line 366, in _run_checks
        return checks.run_checks(**kwargs)
File "/Users/kuldeep/env/lib/python3.7/site-packages/django/core/checks/registry.py", line 71, in run_checks
        new_errors = check(app_configs=app_configs)
File "/Users/kuldeep/env/lib/python3.7/site-packages/django/core/checks/urls.py", line 40, in check_url_namespaces_unique
        all_namespaces = _load_all_namespaces(resolver)
File "/Users/kuldeep/env/lib/python3.7/site-packages/django/core/checks/urls.py", line 67, in _load_all_namespaces
        namespaces.extend(_load_all_namespaces(pattern, current))
File "/Users/kuldeep/env/lib/python3.7/site-packages/django/core/checks/urls.py", line 67, in _load_all_namespaces
        namespaces.extend(_load_all_namespaces(pattern, current))
File "/Users/kuldeep/env/lib/python3.7/site-packages/django/core/checks/urls.py", line 67, in _load_all_namespaces
        namespaces.extend(_load_all_namespaces(pattern, current))
      [Previous line repeated 986 more times]
File "/Users/kuldeep/env/lib/python3.7/site-packages/django/core/checks/urls.py", line 59, in _load_all_namespaces
        ':'.join(parents + (url.namespace,)) for url in url_patterns
File "/Users/kuldeep/env/lib/python3.7/site-packages/django/core/checks/urls.py", line 60, in <listcomp>
        if getattr(url, 'namespace', None) is not None
    RecursionError: maximum recursion depth exceeded while calling a Python object

我期望飞行的火箭使我对本地主机上的祝贺消息充满信心。

mysite / urls.py文件：

from django.contrib import admin
from django.urls import include, path

urlpatterns = [
    path('polls/', include('polls.urls')),
    path('admin/', admin.site.urls),
]

polls / urls.py文件：

from django.urls import include, path
from django.contrib import admin
from . import views

urlpatterns = [
    path('polls/', include ('polls.urls')),
    path ('admin/', admin.site.urls),
]

polls / views.py代码：

from django.shortcuts import render

# Create your views here.
from django.http import HttpResponse

def index(request):
  return HttpResponse("Hello, world. You are at the polls index")

Answer 1

查看您的urlpatterns的 polls / urls.py 代码，其中包括自身，这会导致无休止的循环。

您的 polls / urls.py 应该包含特定于 polls 应用的子路径。由于此应用只有一个视图，因此您可能只需要一个路径：

path('', views.index)

请记住， my_site / urls.py 包含在polls/路径下，因此获取index视图的完整路径为：“ / polls / “。

您可能正在做Django教程，请检查代码here

我无法从Django框架中解决RecursionError

1 个答案: