Redux如何使用Fetch方法调度多种动作类型

时间:2019-02-13 12:40:21

标签: reactjs redux redux-thunk

我正在尝试通过Redux的fetch方法进行api调用,我创建了一些操作类型,例如fetch_start,fetch_success和fetch_failed。

但是我不能让我的减速器一无所有。当我检查redux dev工具时,也有3种动作类型起作用。我在哪里错了?

我正在使用thunk,redux

这是我的组件:

class SignInComponent extends Component {

    signIn = () => {
        this.props.signIn()
    }

    render() {

    return (
      <Row className="justify-content-md-center">
         <Col lg={4}>
              <button type="button" onClick={this.signIn}>
              </button>
              </Col>
      </Row>
    )
  }
}


  const mapStateToProps = state => ({
    users: state.users
  })

  function mapDispatchToProps(dispatch) {
    return {
      signIn: bindActionCreators(signIn, dispatch)
    }
  } 

  export default connect(mapStateToProps, mapDispatchToProps)(SignInComponent)

这是我的减速器:

import { SIGNIN_START, SIGNIN_SUCCESS, SIGNIN_FAILED } from '../../actions/Auth/SignIn'

let initialState = []

export default (state = initialState, action) => {
    switch (action.type) {
        case SIGNIN_START:
            return console.log('start')
        case SIGNIN_SUCCESS:
            return console.log("success")  
        case SIGNIN_FAILED:
            return console.log("fail")        
        default:
            return state
    }
}

这是我的动作:

export const SIGNIN_START = 'SIGNIN_START';
export const SIGNIN_SUCCESS = 'SIGNIN_SUCCESS';
export const SIGNIN_FAILED = 'SIGNIN_FAILED';

export const signIn = () => {
    return(dispatch) => {
        dispatch({
            type: SIGNIN_START
        })
        fetch('https://api.com/signIn')
        .then((response) => {
            dispatch({
                type: SIGNIN_SUCCESS
            })
        })
        .catch((err) => {
        dispatch({
            type: SIGNIN_FAILED
        })
        })
    }
}

1 个答案:

答案 0 :(得分:1)

您必须为每个操作在化简器中返回新状态

return console.log();

将仅返回undefined

将其更改为

switch (action.type) {
  case SIGNIN_START:
     console.log('start')
     return [...state];
  case SIGNIN_SUCCESS:
     console.log("success")
     return [...state];
  case SIGNIN_FAILED:
     console.log("fail");
     return [...state];    
  default:
     return state
 }