Question

好吧，所以我有一个函数，类型为JSONB，并根据来自该数据块的各种键执行SELECT和INSERT。 PostgreSQL抛出与PERFORM和INSERT有关的错误。在SQL查询中json数据的正确用法是什么？

CREATE OR REPLACE FUNCTION add_revision(d jsonb)
RETURNS jsonb AS $$
DECLARE
    did INT;
BEGIN
    did:=get_drawing_id(d->>'Name');
    IF did=NULL THEN
        did:=create_drawing(d->>'Name',d->>'Discipline',
            d->>'Doc Type');
    END IF;
    PERFORM * FROM revisions WHERE drawingid=did AND Sequence=d->>'Sequence';
    IF NOT FOUND THEN
        INSERT INTO revisions (Sequence,Revision,State,Meta) VALUES(d->>'Sequence',
            d->>'Version',d->>'State',d);
        RETURN jsonb_build_object('ok',true);
    END IF;
    RETURN jsonb_build_object('ok',false,'message','Already exists');
END;
$$ LANGUAGE plpgsql;

这是抛出错误的地方

Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42883]: Un
defined function: 7 ERROR:  operator does not exist: integer = text
LINE 1: ... * FROM revisions WHERE drawingid=did AND Sequence=(d->>'Seq...

Answer 1

您不能将整数与文本进行比较。 PostgreSQL是严格的。

在此部分检查类型。

 drawingid=did AND Sequence=d->>'Sequence'

这应该不是与JSONB相关的问题。

Answer 2

在查询中使用JSONB函数非常好，我只需要将类型转换为所需的类型：

CREATE OR REPLACE FUNCTION add_drawing_revision(d jsonb)
RETURNS jsonb AS $$
DECLARE
    did INT;
BEGIN
    did:=get_drawing_id(d->>'Name');
    IF did<0 THEN
        did:=create_drawing(d->>'Name',d->>'Discipline',
            d->>'Doc Type');
    END IF;
    PERFORM * FROM revisions WHERE drawingid=did AND Sequence=(d->>'Sequence')::INT;
    IF NOT FOUND THEN
        INSERT INTO revisions (Sequence,Revision,State,Meta) VALUES((d->>'Sequence')::INT,
            d->>'Version',d->>'State',d);
        RETURN jsonb_build_object('ok',true);
    END IF;
    RETURN jsonb_build_object('ok',false,'message','Already exists');
END;
$$ LANGUAGE plpgsql;

查询涉及通过JSONB传递的数据

2 个答案: