Question

我在线找到了此脚本，我想添加一个提交按钮，将您发送到所选城市。很抱歉这个愚蠢的问题，我是新手。

示例：

下拉菜单选择：比利时->西弗拉德里->布鲁日

页面将您重定向到：

此处是带有演示的https://www.yoursitename.com/city/belgium/west-flanderi/brugge

index.php

<script type="text/javascript">
  $(document).ready(function(){
$('#country').on('change',function(){
    var countryID = $(this).val();
    if(countryID){
        $.ajax({
            type:'POST',
            url:'ajaxData.php',
            data:'country_id='+countryID,
            success:function(html){
                $('#state').html(html);
                $('#city').html('<option value="">Select state first</option>'); 
            }
        }); 
    }else{
        $('#state').html('<option value="">Select country first</option>');
        $('#city').html('<option value="">Select state first</option>'); 
    }
});

$('#state').on('change',function(){
    var stateID = $(this).val();
    if(stateID){
        $.ajax({
            type:'POST',
            url:'ajaxData.php',
            data:'state_id='+stateID,
            success:function(html){
                $('#city').html(html);
            }
        }); 
    }else{
        $('#city').html('<option value="">Select state first</option>'); 
    }
});
  });
  </script>


<?php
//Include database configuration file
include('dbConfig.php');

//Get all country data
$query = $db->query("SELECT * FROM countries WHERE status = 1 ORDER BY country_name ASC");

//Count total number of rows
$rowCount = $query->num_rows;
?>
<select name="country" id="country" >
    <option value="">Select Country</option>
    <?php
    if($rowCount > 0){
        while($row = $query->fetch_assoc()){ 
            echo '<option value="'.$row['country_id'].'">'.$row['country_name'].'</option>';
        }
    }else{
        echo '<option value="">Country not available</option>';
    }
    ?>
</select>

<select name="state" id="state">
    <option value="">Select country first</option>
</select>

<select name="city" id="city">
    <option value="">Select state first</option>
</select>

ajaxData.php

    <?php
    //Include database configuration file
    include('dbConfig.php');

if(isset($_POST["country_id"]) && !empty($_POST["country_id"])){
//Get all state data
$query = $db->query("SELECT * FROM states WHERE country_id =         ".$_POST['country_id']." AND status = 1 ORDER BY state_name ASC");

//Count total number of rows
$rowCount = $query->num_rows;

//Display states list
if($rowCount > 0){
    echo '<option value="">Select state</option>';
    while($row = $query->fetch_assoc()){ 
        echo '<option     value="'.$row['state_id'].'">'.$row['state_name'].'</option>';
    }
}else{
    echo '<option value="">State not available</option>';
    }
}

if(isset($_POST["state_id"]) && !empty($_POST["state_id"])){
//Get all city data
$query = $db->query("SELECT * FROM cities WHERE state_id =     ".$_POST['state_id']." AND status = 1 ORDER BY city_name ASC");

//Count total number of rows
$rowCount = $query->num_rows;

//Display cities list
if($rowCount > 0){
    echo '<option value="">Select city</option>';
    while($row = $query->fetch_assoc()){ 
        echo '<option     value="'.$row['city_id'].'">'.$row['city_name'].'</option>';
    }
}else{
    echo '<option value="">City not available</option>';
}
}
?>

dbConfig.php

    <?php
    //db details
    $dbHost = 'localhost';
    $dbUsername = 'root';
    $dbPassword = '';
    $dbName = 'lisenme';

    //Connect and select the database
    $db = new mysqli($dbHost, $dbUsername, $dbPassword, $dbName);

    if ($db->connect_error) {
    die("Connection failed: " . $db->connect_error);
    }
    ?>

Answer 1

这是您的操作方式：

基本上，您要做的是添加另一个绑定到“城市”选择框更改的事件，例如：

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<select id="dropdown1">
  <option value="one"> One </option>
  <option value="two"> Two </option>
  <option value="three"> Three </option>  
</select>

这是完整的示例： https://jsfiddle.net/4sy9nfg7/1/

如何向此脚本添加功能

1 个答案: