您好，我有一种模式可以验证url，它工作正常，但我想从ip编号中删除所有验证：
const pattern= /^(?:(?:https?):\/\/)?(?:(?!(?:10|127)(?:\.\d{1,3}){3})(?!(?:169\.254|192\.168)(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/\S*)?$/
我尝试删除类似这样的零件：
/^(?:(?:https?):\/\/)?(?:(?!(?:10|127)(?:\.\d{1,3}){3})(?!(?:\.\d{1,3}){2}){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/\S*)?$/
但是我不确定那是否很好
答案 0 :(得分：2)
您可以简单地使用IP regex模式(?!(?:10|127)(?:\.\d{1,3}){3})(?!(?:169\.254|192\.168)(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))删除所有IP regex匹配部分（(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)(?:\.(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)){3}）：
/^(?:https?:\/\/)?(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)(?:\.(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)){3}|(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+(?:\.(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/\S*)?$/
请参见regex demo
详细信息
^-字符串的开头
(?:https?:\/\/)?-可选的字符串匹配https?-http或https :\/\/-一个://子字符串(?:-容器组的开始：(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)(?:\.(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)){3}-IPv4模式|-或
(?:[a-z\u00a1-\uffff0-9]-*)*-在¡（索引161）和``（索引65535）之间，字母，数字或字符的0+次重复，后跟0+连字符[a-z\u00a1-\uffff0-9]+-在¡（索引161）到``（索引65535）之间的1个字母，数字或字符(?:\.(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)*-点的零次或多次重复以及上面的两个子模式(?:\.[a-z\u00a1-\uffff]{2,})-点号后接¡（索引161）和``（索引65535）之间的2个或更多字母，数字或字符重复)-容器组的结尾(?::\d{2,5})?-以:开头，然后是2到5位数字的可选子字符串(?:\/\S*)?-可选的子字符串，以/开头，然后是0+个非空格字符$-字符串的结尾。