我想将我的注释从@RequestMapping替换为@ GetMapping,@ PutMapping ...注释。当我查看IntelliJ中的“结构查找/替换”时,看起来可以完成这项工作。
我尝试在搜索中添加以下内容
@RequestMapping($ key $ = $ value $) 在键上添加了一个过滤器。 text = method。
现在,我想从值(RequestMethod.GET)中提取单词。 (期)。然后在替换中添加
@ [Word(TitleCase)]映射([除搜索结果中提取的键值以外的所有内容]
还无法弄清楚该如何解决。希望知道是否无法完成此操作,或者对如何执行此操作有任何建议。看了SO上的其他一些问题,但没有找到任何可以帮助的问题。在这种情况下,大多数答案是使用正则表达式。
之前:
@RequestMapping(
value = "/channels/{channel_name}",
method = RequestMethod.POST,
produces = MediaType.APPLICATION_JSON_VALUE,
consumes = MediaType.APPLICATION_JSON_VALUE)
public Channel updateChannel(
@PathVariable("channel_name") String channelName,
@Valid @RequestBody Channel channel) {
return channelService.updateChannel(channelName, channel);
}
@RequestMapping(
value = "/channels/{channel_name}",
method = RequestMethod.DELETE,
produces = MediaType.APPLICATION_JSON_VALUE)
public Channel deleteChannel(
@PathVariable("channel_name") String channelName) {
return channelService.deleteChannel(channelName);
}
之后
@PostMapping(value = "/channels/{channel_name}",
produces = MediaType.APPLICATION_JSON_VALUE,
consumes = MediaType.APPLICATION_JSON_VALUE)
public Channel updateChannel(
@PathVariable("channel_name") String channelName,
@Valid @RequestBody Channel channel) {
return channelService.updateChannel(channelName, channel);
}
@DeleteMapping(
value = "/channels/{channel_name}",
produces = MediaType.APPLICATION_JSON_VALUE)
public Channel deleteChannel(
@PathVariable("channel_name") String channelName) {
return channelService.deleteChannel(channelName);
}
答案 0 :(得分:0)
我会用正则表达式来处理这个问题
RequestMethod.(.)(.+)(?=,)
替换为RequestMethod.\U$1\L$2
(\L would turn the text into lowercase。)@RequestMapping\((\s+)(.+)(\s+?)(.+)RequestMethod.(.+?),
替换为@$5Mapping\($1$2$3
。然后简化此替换链:
将 @RequestMapping\((\s+)(.+)(\s+?)(.+)RequestMethod.(\S)(.+?),
替换为@\U$5\L$6\EMapping\($1$2
更新:注意,无论在value
行还是独立行中都未指定第一个参数@Mapping
。
@Mapping
行中需要它,请将@RequestMapping\((\s+)(.+)(\s+?)(.+)RequestMethod.(\S)(.+?),\s
替换为@\U$5\L$6\EMapping\($2$3
。@RequestMapping\((\s+)(.+)(\s+?)(.+)RequestMethod.(\S)(.+?),
替换为@\U$5\L$6\EMapping\($1$2
。