Question

我的功课有问题。我的目标是要比较第一列第一行和第二列第二行。

我是熊猫新手，所以我尝试在互联网上浏览答案，但可惜没有。我想到了一种方法，将熊猫转换为数组并将第一列存储到第一数组，将第二列存储到第二数组。

first_array = [4,10,17,24,82,93,35,40,49,71,78]
last_array = [9,16,23,29,89,97,39,48,57,77,85]

然后我弹出first_array的第一个数字是4，然后在最后一个这样的数字中插入一个0

first_array = [10,17,24,82,93,35,40,49,71,78, 0]
last_array =  [ 9,16,23,29,89,97,39,48,57,77,85]

还有一点for循环

if first_array < last_array:
   print ("===")

但是看来我的逻辑是正确的，但是我期望的输出有一点错误

['10', '17', '24', '82', '93', '35', '40', '49', '71', '78', '0']
['9', '16', '23', '29', '89', '97', '39', '48', '57', '77', '85']
===
['17', '24', '82', '93', '35', '40', '49', '71', '78', '0']
['16', '23', '29', '89', '97', '39', '48', '57', '77', '85']
['24', '82', '93', '35', '40', '49', '71', '78', '0']
['23', '29', '89', '97', '39', '48', '57', '77', '85']
['82', '93', '35', '40', '49', '71', '78', '0']
['29', '89', '97', '39', '48', '57', '77', '85']
['93', '35', '40', '49', '71', '78', '0']
['89', '97', '39', '48', '57', '77', '85']
['35', '40', '49', '71', '78', '0']
['97', '39', '48', '57', '77', '85']
===
['40', '49', '71', '78', '0']
['39', '48', '57', '77', '85']
['49', '71', '78', '0']
['48', '57', '77', '85']
['71', '78', '0']
['57', '77', '85']
['78', '0']
['77', '85']
['0']
['85']
===

第一个“ ===” 10不是<9，这让我思考。我错过了什么？预先谢谢你。

这是我的代码的一部分。 print（join_tag）是我为此所需的输出。

normalized_text = []
first_array = [10,17,24,82,93,35,40,49,71,78, 0]
last_array =  [ 9,16,23,29,89,97,39,48,57,77,85]
for word in normalized_text:
    join_tag = ' '.join(word)
    print (join_tag)
    if first_array < last_array:
        print ('===')
        first_array.pop(0)
        last_array.pop(0)

预期输出为

['10', '17', '24', '82', '93', '35', '40', '49', '71', '78', '0']
['9', '16', '23', '29', '89', '97', '39', '48', '57', '77', '85']
['17', '24', '82', '93', '35', '40', '49', '71', '78', '0']
['16', '23', '29', '89', '97', '39', '48', '57', '77', '85']
['24', '82', '93', '35', '40', '49', '71', '78', '0']
['23', '29', '89', '97', '39', '48', '57', '77', '85']
['82', '93', '35', '40', '49', '71', '78', '0']
['29', '89', '97', '39', '48', '57', '77', '85']
['93', '35', '40', '49', '71', '78', '0']
['89', '97', '39', '48', '57', '77', '85']
['35', '40', '49', '71', '78', '0']
['97', '39', '48', '57', '77', '85']
===
['40', '49', '71', '78', '0']
['39', '48', '57', '77', '85']
['49', '71', '78', '0']
['48', '57', '77', '85']
['71', '78', '0']
['57', '77', '85']
['78', '0']
['77', '85']
['0']
['85']
===

Answer 1

如果我正确理解了您的问题，您想将4与16进行比较，对吧？

如果是，则将数据放回数据框中：

import numpy as np
import pandas as pd

first_array = np.array([4,10,17,24,82,93,35,40,49,71,78])
last_array = np.array([9,16,23,29,89,97,39,48,57,77,85])
df = pd.DataFrame(np.vstack((first_array, last_array)))

然后：

df.iloc[0, 0] < df.iloc[1, 1]

会比较4个<16

要全部比较：

for i in range(len(df.columns)-1):
    print(df.iloc[0, i] < df.iloc[1, i+1])

Answer 2

您的数组包含字符串。将它们转换为数字。在第一种情况下，'10'<'9'为真，因为字符串'10'在字母上小于字符串'9'

如何比较第一列和第二列

2 个答案: