Question

我想两个一起开始两个动画。

第一个动画是交易动画

 val transaction = supportFragmentManager.beginTransaction()
    transaction.setCustomAnimations(R.anim.slide_in_right, R.anim.slide_out_left, R.anim.slide_in_left, R.anim.slide_out_right)
    transaction.replace(R.id.container, fragment, fragment::javaClass.name)
    transaction.addToBackStack(fragment::javaClass.name)
    transaction.commit()

第二个动画是活动中的搜索栏动画

abstract class BaseProgressFragment : BaseFragment() {

abstract val progressCount: Int

abstract val seekBar: NonEnabledSeekBar

abstract val tvProgress: TextView

override fun onViewCreated(view: View, savedInstanceState: Bundle?) {
    super.onViewCreated(view, savedInstanceState)
    animateProgress()
}

private fun animateProgress() {
    val progress = "$progressCount%"
    val progressAnimator = ObjectAnimator.ofInt(seekBar, "progress", seekBar.progress, progressCount * 100)
    progressAnimator.duration = 600
    progressAnimator.interpolator = LinearInterpolator()
    progressAnimator.start()
    seekBar.progress = progressCount * 100
    tvProgress.text = progress
}}

在子片段中

override val seekBar: NonEnabledSeekBar
    get() = (activity as CreateOrderActivity).sbCreatingOrder

当我仅启动1个动画就可以了，但是当我尝试启动它们时，它们会一起冻结UI。

请告诉我如何解决这个问题。

Answer 1

我可以解决

seekBar.setLayerType(View.LAYER_TYPE_HARDWARE, null)

和

val progressAnimator = ObjectAnimator.ofInt(seekBar, "progress", seekBar.progress, progressCount * 100)
        progressAnimator.duration = 600
        progressAnimator.interpolator = LinearInterpolator()
        progressAnimator.addListener(object : AnimatorListenerAdapter() {
            override fun onAnimationEnd(animation: Animator) {
                seekBar.setLayerType(View.LAYER_TYPE_NONE, null)
            }
        })
        progressAnimator.start()

一起开始两个动画

1 个答案: