Question

我有多行纯文本，每行混有带/不带双引号的短语。我想删除所有包含引号的内容，但保留双引号中的内容。示例：

int (*)[1][2]

结果应为：

    /// <summary>
    /// Create a list of the given anonymous class. <paramref name="definition"/> isn't called, it is only used
    /// for the needed type inference. This overload is for when you don't have an instance of the anon class
    /// and don't want to make one to make the list.
    /// </summary>
    /// <typeparam name="T"></typeparam>
    /// <param name="definition"></param>
    /// <returns></returns>
#pragma warning disable RECS0154 // Parameter is never used
    public static List<T> CreateListOfAnonType<T>(Func<T> definition)
#pragma warning restore RECS0154 // Parameter is never used
    {
        return new List<T>();
    }
    /// <summary>
    /// Create a list of the given anonymous class. <paramref name="definition"/> isn't added to the list, it is
    /// only used for the needed type inference. This overload is for when you do have an instance of the anon
    /// class and don't want the compiler to waste time making a temp class to define the type.
    /// </summary>
    /// <typeparam name="T"></typeparam>
    /// <param name="definition"></param>
    /// <returns></returns>
#pragma warning disable RECS0154 // Parameter is never used
    public static List<T> CreateListOfAnonType<T>(T definition)
#pragma warning restore RECS0154 // Parameter is never used
    {
        return new List<T>();
    }

Answer 1

:%s/.*\"\(.*\)\".*/\1

说明

REPLACE, ANY_STRING, QUOTES, CAPTURE_ANY_STRING,   QUOTES,  ANY_STRING WITH
  :%s/     .*        \"      \(     .*     \)       \"         .* .    /\1

Answer 2

如果光标位于该行的开头，则可以执行以下操作：

f"lyi"Vp

f"l将光标移到“第一个”，然后再留出一个空格

yi"将s中的所有内容移至匿名注册人

Vp在可视模式下选择整行，然后在其上粘贴匿名寄存器

要应用于多行，请使用normal命令。

:%normal 0f"lyi"Vp

:进入命令模式

%将范围设置为整个文件

normal执行以下击键，就像在普通模式下一样输入

0将光标移动到行首

f"lyi"Vp参见上文

在Vim中，如何删除所有内容，但保留双引号？

2 个答案: