如何根据时间戳确定一周的第一天和最后一天？

Question

我有一张包含以下数据的表：

trtime:2019-01-31 11:03:33.000 || tr_count:1
trtime:2019-01-31 11:23:33.000 || tr_count:2
trtime:2019-01-31 12:13:33.000 || tr_count:5
trtime:2019-01-31 12:43:33.000 || tr_count:1

我想以这种格式输出：

time_till:2019-01-31 12:00:00.000 || tr_count:3
time_till:2019-01-31 13:00:00.000 || tr_count:6

即每小时合并一次。

谢谢

Answer 1

您可以将from libcloud.compute.types import Provider from libcloud.compute.providers import get_driver driver = get_driver(Provider.EC2) driver.list_regions() ['ap-northeast-1', 'ap-northeast-2', 'ap-northeast-3', 'ap-south-1', 'ap-southeast-1', 'ap-southeast-2', 'ca-central-1', 'cn-north-1', 'cn-northwest-1', 'eu-central-1', 'eu-west-1', 'eu-west-2', 'eu-west-3', 'sa-east-1', 'us-east-1', 'us-east-2', 'us-gov-west-1', 'us-west-1', 'us-west-2'] 与casting一起使用，以将类型转换为下面的查询

grouping

Demo

Answer 2

WITH TempResult as
(select CONVERT(date, time) myDate, DATEPART(HOUR, time)+1 myHour,count(id) tr_count
from myTable
GROUP BY CONVERT(date, time), DATEPART(HOUR, time))
Select DATEADD(hour,myHour+1,Convert(Datetime, myDate)) time_till,tr_count   from TempResult