在上一篇文章中,我像这样在temp表中获取了所有数据
select * from #MyTempEmployeeTable
数据:
version count1 productname
------------------------------------------
10.0 2 Windows client Update
10.0 10 Windows client Update
10.0 486 Windows client Update
10.0.1 1 Windows client Update
10.0.1 2 Windows client Update
10.0.1 7 Windows client Update
10.0.1 9 Windows client Update
10.0.1 10 Windows client Update
10.0.1 56 Windows client Update
10.0.1 159 Windows client Update
10.0.1 233 Windows client Update
10.0.14 2 Windows client Update
10.0.14 3 Windows client Update
10.0.14 84 Windows client Update
10.0.14 265 Windows client Update
10.0.15 11 Windows client Update
10.0.15 29 Windows client Update
10.0.15 277 Windows client Update
10.0.15 8456 Windows client Update
10.0.18 1 Windows client Update
7.4.76 571 Windows client Update
7.5.7601 27 Windows client Update
7.6.76 1 Windows client Update
7.6.76 606 Windows client Update
7.6.7601 10 Windows client Update
7.6.7601 80 Windows client Update
7.6.7601 128 Windows client Update
7.6.7601 6491 Windows client Update
7.6.7601 51079 Windows client Update
7.8.9200 2 Windows client Update
7.8.9200 171 Windows client Update
7.9.9600 1 Windows client Update
7.9.9600 8 Windows client Update
7.9.9600 11 Windows client Update
7.9.9600 15 Windows client Update
7.9.9600 18 Windows client Update
7.9.9600 41 Windows client Update
7.9.9600 200 Windows client Update
7.9.9600 2026 Windows client Update
我正在编写以下查询,以按版本对分组进行计数,但它没有返回预期的结果。
select count(count1), version
from #MyTempEmployeeTable
group by version
运行此查询后,我没有得到适当的数据
(No column name) version
------------------------------
3 10.0
8 10.0.1
4 10.0.14
4 10.0.15
1 10.0.18
1 7.4.76
1 7.5.7601
2 7.6.76
5 7.6.7601
2 7.8.9200
8 7.9.9600
能帮我一下吗?对于10.0版,理想情况下,我应该将数据作为496
答案 0 :(得分:2)
您要sum()
,而不是count()
:
select sum(count1), version
from #MyTempEmployeeTable
group by version
答案 1 :(得分:2)
我认为您不希望sum()
不计算
select sum (count1),version
from #MyTempEmployeeTable group by version
答案 2 :(得分:1)
我认为您需要使用SUM
select sum(count1),
version
from #MyTempEmployeeTable
group by version
count是行数,sum是列中值的总和。
,对于10.0版,您将获得498(486 + 10 + 2),而不是问题中的496。