在将ggplot转换为可打印对象并保留相同的图例属性时遇到一些问题。我想要什么:
以下是显示我根据此答案尝试的2种方法的代码: ggplot: remove lines at ribbon edges
运行时,两者都会产生不良影响。任何建议都会很棒:)
library(plotly)
library(ggplot2)
# fake data
set.seed(1)
dt <- data.frame(x=rep(1:7,2), group=rep(letters[1:2], each=7), value=runif(14))
dt$lwr <- dt$value*.9
dt$upr <- dt$value*1.1
# build plot in ggplot, don't want lines at the edge
pl <- ggplot(data=dt, aes(y=value, x=x, group=group, colour=group,
fill=group)) +
geom_point() +
geom_line() +
geom_ribbon(aes(ymin=lwr, ymax=upr), alpha=.3, linetype=0) +
theme_minimal()
# looks ok, no lines at the edges
pl
# lines at edges, single group
ggplotly(pl)
# alternative: try reverting colour to NA
pl2 <- ggplot(data=dt, aes(y=value, x=x, group=group, colour=group,
fill=group)) +
geom_point() +
geom_line() +
geom_ribbon(aes(ymin=lwr, ymax=upr), alpha=.3, colour=NA) +
theme_minimal()
# looks ok
pl2
# no lines, but now not grouped, and some weird naming
ggplotly(pl2)
谢谢,强尼
编辑: 以功能形式添加已接受的答案
# dd: ggplotly object
library(stringi)
library(rvest)
remove_ggplotly_ribbon_lines <- function(dd){
find <- rvest::pluck(dd$x$data, "fillcolor")
w <- which(!sapply(find, is.null))
for(i in w){
dd$x$data[[i]]$line$color <-
stringi::stri_replace_all_regex(dd$x$data[[i]]$line$color, ",[\\d.]*\\)$", ",0.0)")
}
return(dd)
}
remove_ggplotly_ribbon_lines(ggplotly(pl))
答案 0 :(得分:1)
您好,这不是评论,而是答案,但我无权发表评论。
如果调查ggplotly对象,您会发现它实际上只是一个列表。更改列表的正确元素有助于控制打印选项。
下面的解决方案仅更改功能区边缘处的线的alpha。希望这会有所帮助
library(plotly)
set.seed(1)
dt <- data.frame(x=rep(1:7,2), group=rep(letters[1:2], each=7), value=runif(14))
dt$lwr <- dt$value*.9
dt$upr <- dt$value*1.1
# build plot in ggplot, don't want lines at the edge
pl <- ggplot(data=dt, aes(y=value, x=x, group=group, colour=group,
fill=group)) +
geom_point() +
geom_line() +
geom_ribbon(aes(ymin=lwr, ymax=upr), alpha=.3, linetype=0) +
theme_minimal()
# looks ok, no lines at the edges
pl
# no lines at edges
dd = ggplotly(pl)
dd$x$data[[3]]$line$color = "rgba(248,118,109,0.0)"
dd$x$data[[4]]$line$color = "rgba(0,191,196,0.0)"
dd