Question

我首先从表'properties'获取属性，然后运行内部查询以从单独的表'property_images'获取图像。这是一个缓慢的方法。指导我如何在api请求中的单个查询中获取属性和图像？

public function searchProperty(Request $request){
        if(count($request->all()) > 0){
            $properties = array();
            $properties = \DB::table('properties')
            ->where($request->all())
            ->get()->toArray();
            $prop_ids = array();
            if(isset($properties) && !empty($properties) && count($properties) > 0){
                foreach($properties as $prop){
                    array_push($prop_ids, $prop->id);
                }
                $prop_images = \DB::table('property_images')
                    ->whereIn('property_id', $prop_ids)
                    ->get()->toArray();
                if(isset($prop_images) && !empty($prop_images)){
                    foreach($prop_images as $imgs){
                        $upload_path = storage_path() . '/uploads/property/' . $imgs->property_id .'/'.$imgs->property_image;
                        array_push($properties, $upload_path);
                    }
                }
                echo '<pre>'; print_r($properties); exit;
                return response()->json([
                    'success' => true,
                    'data' => $properties->toArray()
                ], 400);
            }
        }
        else{
            return response()->json([
                'success' => false,
                'message' => 'No data available'
            ], 500);
        }
    }

Answer 1

尝试此查询，它必须对您有用，以便仅通过单个查询即可获取所有属性及其所有图像。图片将以逗号分隔，您将在单个产品行中看到它。您必须以逗号爆炸。如果您编写任何api，都可以用图像连接完整的url。

    DB::table('properties')
    ->selectRaw('GROUP_CONCAT(property_images.property_image) as 
    property_images, properties.*')
    ->leftJoin('property_images', 'property_images.property_id', '=', 'properties.id')
    ->groupBy('properties.id')
    ->get()->toArray();

修改Laravel查询以在单个查询中获取属性和图像，而不是单独的图像子查询

1 个答案: