通过@ManyToMany关联加入三个表
我正在使用Spring Boot和Spring Data JPA实现Book Store应用程序。我已经尝试过@onetoone和@manytoone和@onetomany关联,但是我对@ManyToMany关联感到困惑。
共有三个表格-图书,类型和作者。我想做以下 1)创建一个新表-Book_Genre_Author 2)如果数据库中已经存在Author或Genre,则不会在数据库中创建新条目。 3)如果Book已经存在于数据库中,则不会进入数据库。 4)如何使用Spring Data JPA实施插入和更新操作?
这是我的三个实体-
@Entity
@Table(name = "Book_Details")
public class Book {
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "CUSTOM_SEQUENCE")
@SequenceGenerator(sequenceName = "customer_seq", allocationSize = 1, name = "CUSTOM_SEQUENCE")
@Column(name = "BookId")
int bookId;
public int getBookId() {
return bookId;
}
public void setBookId(int bookId) {
this.bookId = bookId;
}
@Column(name = "BookName")
String bookName;
@ManyToMany(cascade=CascadeType.ALL)
@JoinTable(name = "Book_Author_Genre", joinColumns = @JoinColumn(name = "bookId"), inverseJoinColumns = @JoinColumn(name = "genreId"))
@MapKeyJoinColumn(name = "authorId")
@ElementCollection
private Map<Author, Genre> authorGenre = new HashMap<>();
public Map<Author, Genre> getAuthorGenre() {
return authorGenre;
}
public void setAuthorGenre(Map<Author, Genre> authorGenre) {
this.authorGenre = authorGenre;
}
@Column(name = "Language")
String language;
@Column(name = "GoodReadReviews")
String goodReadReviews;
@Override public String toString() { return "BookId=" + this.bookId +
"::BookName=" + this.bookName + "::AuthorId=" + "Will check how to get it" +
"::Langauge = " + this.language + "::GenreId = " + "Will check how to get it" +
"::GoodReadReviews=" + this.goodReadReviews;
}
public String getBookName() {
return bookName;
}
public void setBookName(String bookName) {
this.bookName = bookName;
}
public String getLanguage() {
return language;
}
public void setLanguage(String language) {
this.language = language;
}
public String getGoodReadReviews() {
return goodReadReviews;
}
public void setGoodReadReviews(String goodReadReviews) {
this.goodReadReviews = goodReadReviews;
}
}
@Entity
@Table(name="Author_Details")
public class Author {
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator="AuthorSeqGenerator")
@SequenceGenerator(sequenceName = "author_seq", allocationSize = 1, name = "AuthorSeqGenerator")
@Column(name="AuthorId")
int authorId;
@Column(name="AuthorName")
String authorName;
@Column(name="Country")
String country;
@Column(name="Gender")
String gender;
public int getAuthorId() {
return authorId;
}
public void setAuthorId(int authorId) {
this.authorId = authorId;
}
public String getAuthorName() {
return authorName;
}
public void setAuthorName(String authorName) {
this.authorName = authorName;
}
public String getCountry() {
return country;
}
public void setCountry(String country) {
this.country = country;
}
public String getGender() {
return gender;
}
public void setGender(String gender) {
this.gender = gender;
}
}
@Entity
@Table(name="Genre_details")
public class Genre {
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator="GenreSeqGenerator")
@SequenceGenerator(sequenceName = "genre_seq", allocationSize = 1, name = "GenreSeqGenerator")
int genreId;
@Column(name="GenreName")
String genreName;
public int getGenreId() {
return genreId;
}
public void setGenreId(int genreId) {
this.genreId = genreId;
}
public String getGenreName() {
return genreName;
}
public void setGenreName(String genreName) {
this.genreName = genreName;
}
}
我尝试使用以下代码保存图书详细信息-
Author author = new Author();
author.setAuthorName("Rabindranath Tagore");
author.setCountry("India");
author.setGender("Male");
Genre genre = new Genre();
genre.setGenreName("Fiction");
Book book = new Book();
book.setBookName("Gitanjali");
book.setGoodReadReviews("5");
book.setLanguage("Bengali");
HashMap<Author,Genre> authorGenre = new HashMap<>();
authorGenre.put(author, genre);
book.setAuthorGenre(authorGenre);
bookRepository.save(book);
但是我收到以下错误消息。
原因:org.springframework.dao.InvalidDataAccessApiUsageException:org.hibernate.TransientObjectException:对象引用了未保存的瞬态实例-在刷新之前保存该瞬态实例:com.bsm.app.model.Author;嵌套异常是java.lang.IllegalStateException:org.hibernate.TransientObjectException:对象引用了一个未保存的瞬态实例-在刷新之前保存该瞬态实例:com.bsm.app.model.Author
我天真,我的做法可能是错误的。请提出建议和支持。
答案 0 :(得分:1)
我建议创建一个新的链接实体,该实体将用于映射该特定表。
您只需决定是使用复合主键还是添加人工ID(推荐)。
此设置似乎涉及更多的编码,但是根据我的经验,一旦3个表开始起作用,就会更加清楚:
class Book {
@OneToMany(mappedBy = "book", cascade = {CascadeType.PERSIST, CascadeType.MERGE})
private Set<BookAuthorGenreLink> bookAuthorGenreLinks;
}
class Author{
@OneToMany(mappedBy = "author", cascade = {CascadeType.PERSIST, CascadeType.MERGE})
private Set<BookAuthorGenreLink> bookAuthorGenreLinks;
}
class Genre{
@OneToMany(mappedBy = "genre", cascade = {CascadeType.PERSIST, CascadeType.MERGE})
private Set<BookAuthorGenreLink> bookAuthorGenreLinks;
}
链接表:
class BookAuthorGenreLink {
@Id
@GeneratedValue
private Long id;
@ManyToOne(cascade = {CascadeType.PERSIST, CascadeType.MERGE})
@JoinColumn(name = "book_id")
private Book book;
@ManyToOne(cascade = {CascadeType.PERSIST, CascadeType.MERGE})
@JoinColumn(name = "author_id")
private Author author;
@ManyToOne(cascade = {CascadeType.PERSIST, CascadeType.MERGE})
@JoinColumn(name = "genre_id")
private Genre genre;
}