无法将fileupload.postedfile.inputstream作为附件发送-错误:无法将system.io.stream转换为字符串

时间:2019-02-12 07:02:33

标签: c# asp.net email

我需要发送pdf作为附件。我正在使用HTML模板作为邮件正文。我的问题是,尝试按如下所示发送附件时显示了错误。

email.Attachments.Add(new Attachment(FileUpload1.PostedFile.InputStream), pdffilename);

FileUpload1.PostedFile.InputStream是错误代码。

我的完整代码显示在下面:

private void send_job_notification(string name, string app_email, string job_id, string job_title, string experience,string pdffilename)
    {
        string to = "aaa@bbb.com";
        SmtpClient smtp_server = new SmtpClient();
        MailMessage email = new MailMessage("aaa@bbb.com", to);
        smtp_server.DeliveryMethod = SmtpDeliveryMethod.Network;
        smtp_server.UseDefaultCredentials = false;
        smtp_server.Credentials = new System.Net.NetworkCredential("aaa@bbb.com", "PASSWORD");
        smtp_server.Port = 25;
        smtp_server.EnableSsl = false;
        smtp_server.Host = "zzz.bbb.com";
        email.From = new MailAddress("aaa@bbb.com");
        email.To.Add(to);
        email.Subject = "New Job request submitted for company";
        email.Attachments.Add(new Attachment(FileUpload1.PostedFile.InputStream), pdffilename);
        email.IsBodyHtml = true;
        string FilePath = Server.MapPath("~/emailnewtemplate.html");
        StreamReader str = new StreamReader(FilePath);
        string MailText = str.ReadToEnd();
        str.Close();
        string line1 = "<h4>Dear Management</h4>";
        string line2 = "<h4>A new job request has been receieved. The applicant details are as follows</h4>";
        string table_open = "<table class='table table-responsive-sm'>";
        string row_1 = "<tr><td>Name : </td><td> " + name + " </td></tr>";
        string row_2 = "<tr><td>Email : </td><td> " + app_email + " </td></tr>";
        string row_3 = "<tr><td>Job ID : </td><td> " + job_id + " </td></tr>";
        string row_4 = "<tr><td>Job Title : </td><td> " + job_title + " </td></tr>";
        string row_5 = "<tr><td>Experience : </td><td> " + experience + " </td></tr>";
        string table_close = "</table>";
        string line3 = table_open + row_1 + row_2 + row_3 + row_4 + row_5 + table_close;
        string htmlbody = line1 + line2 + line3;
        MailText = MailText.Replace("[#####HERE#####]", htmlbody);
        email.Body = MailText;
        smtp_server.Send(email);
   }

1 个答案:

答案 0 :(得分:0)

我认为您的问题是放置在错误的括号中,您似乎尝试使用Attachment类的构造函数Attachment(Stream, String),但仅提供了流。仅接受一个参数的Attachment类的构造函数期望错误消息说的是一个字符串

更正为:

email.Attachments.Add(new Attachment(FileUpload1.PostedFile.InputStream, pdffilename));