Question

l2=[[13,11,9],[7,5,3],[1]]

我想将列表l2中的每个子列表乘以一个常数，即13 * 1,11 * 1,9 * 1和7 * 2,5 * 2,3 * 2和1 * 3，以及最终结果将是13,11,9和14,10,6和3。

Answer 1

使用enumerate

例如：

l2=[[13,11,9],[7,5,3],[1]]
print([[j*i for j in v] for i, v in enumerate(l2, 1)])

输出：

[[13, 11, 9], [14, 10, 6], [3]]

Answer 2

您可以在此处利用enumerate：

l2 = [[13,11,9],[7,5,3],[1]]

l3 = [[x * (idx + 1) for x in sublist] for idx, sublist in enumerate(l2)]
print(l3)

这产生

[[13, 11, 9], [14, 10, 6], [3]]

Answer 3

尝试一下：

l2=[[13,11,9],[7,5,3],[1]]

counter = 1
for i in range(len(l2)):
    for j in range(len(l2[i])):
        l2[i][j] *= counter        
    counter += 1

print(l2)

Answer 4

是否总是第一个子列表是1，第二个是两个，依此类推？

for i in range(0, len(l2)):
    i += 1
    print(f'{l2[i-1]} times {i}')
    print(list(map(lambda x: x*i, l2[i-1])))

Answer 5

一个带有map和enumerate的衬纸

[map((idx).__mul__, sublist) for idx,sublist in enumerate(l2,1)] #[[13, 11, 9], [14, 10, 6], [3]]

使用numpy.multiply

import numpy as np
[np.multiply(sublist,[idx]).tolist() for idx,sublist in enumerate(l2,1)]

Answer 6

new_list = []
multiplier = 1 
# passing over sublists( e.g. [13,11,9] = li) in l2
for li in l2: 
    # multiply all elements in sublist(li) with multiplier(in first step multiplier = 1)
    # append the multiplied sublist to the new list
    new_list.append([li[i]*multiplier for i in range(len(li))])
    # multiplier increase by one (e.g. in second step we need to multiply elements from second sublist with multiplier = 2)
    multiplier += 1
print (new_list)

将每个子列表乘以一个常数

6 个答案: